Home
Class 11
CHEMISTRY
Deduce (a) Boyle's law and (b) Charles l...

Deduce (a) Boyle's law and (b) Charles law from Kinetic gas equation.

Text Solution

Verified by Experts

(a) Boyle.s law : According to kinetic theory the averge K.E of gas molecules is directly proportional to the absolute temperature.
(i.e.) `KE prop "T. But K.E" = (1)/(2) mnc^(2)`
`therefore (1)/(2) mnc^(2) prop T (or) (1)/(2) mnc^(2) = KT`
According to kinetic gas equation, `PV = (1)/(3) mnc^(2)`
(or) `PV = (2)/(3) xx (1)/(2) mnc^(2) (or) PV = (2)/(3) xx KT (or) V = (2)/(3) (K)/(P) T`
If .T. is kept constant, then V = Constant `xx (1)/(P) (or) V prop (1)/(P)` (T constant)
At constant temperature, the volume of a given mass of gas is inversely proportional to its pressure. This is Boyle.s law.
(b) Charles. law : According to kinetic theory, the average K.E of gas molecules is directly proportional to the absolute temperature.
(i.e.) `K.E prop "T. But K.E" = (1)/(2) mnc^(2)`
`therefore (1)/(2) mnc^(2) prop T (or) (1)/(2) mnc^(2) = KT`
According to kinetic gas equation, `PV = (1)/(3) mnc^(2)`
(or) `PV = (2)/(3) xx (1)/(2) mnc^(2) (or) PV = (2)/(3) xx KT (or) V = (2)/(3) (KT)/(P)`
If .P. is kept constant, then V = constant `xx` T (or) V `prop` T (P constant)
At constant pressure, the volume of a given mass of gas is directly proprtional to its absolute temperature. This is Charles. law.
Promotional Banner

Topper's Solved these Questions

  • MODEL PAPER 5

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C|3 Videos
  • MODEL PAPER 5

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C|3 Videos
  • MODEL PAPER 4

    VGS PUBLICATION-BRILLIANT|Exercise Section-C|3 Videos
  • MODEL PAPER 6

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C|3 Videos

Similar Questions

Explore conceptually related problems

Deduce (a) Graham's law and (b) Daltons law from Kinetic gas equation.

Deduce Charle's kaw from kinetic gas equation.