On being warmed with silver powder, chloroform gives

Options

A. `C_6H_6`
B. `C_2H_4`
C. `C_2H_2`
D. `CH_3Cl`

Answer

To solve the question regarding the reaction of chloroform (CHCl3) with silver powder (Ag), we can follow these steps:

### Step 1: Identify the reactants
The reactants in this reaction are chloroform (CHCl3) and silver powder (Ag).

### Step 2: Understand the reaction type
When chloroform is warmed with silver powder, a reaction occurs that involves the substitution of chlorine atoms in chloroform. Silver acts as a reducing agent, and it promotes the formation of acetylene (C2H2) and silver chloride (AgCl).

### Step 3: Write the unbalanced chemical equation
The initial unbalanced reaction can be written as:
\[ \text{CHCl}_3 + \text{Ag} \rightarrow \text{C}_2\text{H}_2 + \text{AgCl} \]

### Step 4: Balance the chemical equation
To balance the equation, we need to ensure that the number of atoms of each element on the reactant side is equal to that on the product side. The balanced equation is:
\[ 2 \text{CHCl}_3 + 6 \text{Ag} \rightarrow 2 \text{C}_2\text{H}_2 + 6 \text{AgCl} \]

### Step 5: Identify the products
From the balanced equation, we can see that the products of the reaction are:
- Acetylene (C2H2)
- Silver chloride (AgCl)

### Final Answer
On being warmed with silver powder, chloroform gives acetylene (C2H2) and silver chloride (AgCl).

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