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At 273°C and 380 torr pressure, the dens...

At 273°C and 380 torr pressure, the density of a gas is 1.25`kg//m^(3)` . So its density at STP in g/l is

A

5 g/l

B

2.5 g/l

C

10 g/l

D

0.5 g/l

Text Solution

AI Generated Solution

The correct Answer is:
To find the density of the gas at Standard Temperature and Pressure (STP) in grams per liter (g/L), we can follow these steps: ### Step 1: Convert the given temperature to Kelvin The temperature is given as 273°C. To convert Celsius to Kelvin, we use the formula: \[ T(K) = T(°C) + 273 \] So, \[ T_1 = 273 + 273 = 546 \, K \] **Hint:** Remember that to convert Celsius to Kelvin, you always add 273. ### Step 2: Identify the given values We have the following values: - Pressure \( P_1 = 380 \, \text{torr} \) - Density \( D_1 = 1.25 \, \text{kg/m}^3 \) - Temperature \( T_1 = 546 \, K \) - At STP, \( P_2 = 760 \, \text{torr} \) and \( T_2 = 273 \, K \) **Hint:** Make sure to note the conditions for STP: 0°C (273 K) and 1 atm (760 torr). ### Step 3: Use the density relation for gases We can use the formula relating the densities at two different conditions: \[ \frac{P_1}{D_1 T_1} = \frac{P_2}{D_2 T_2} \] Rearranging gives us: \[ D_2 = \frac{P_2 D_1 T_1}{P_1 T_2} \] **Hint:** This formula comes from the ideal gas law and relates pressure, density, and temperature. ### Step 4: Substitute the known values into the equation Now we substitute the known values into the equation: \[ D_2 = \frac{760 \, \text{torr} \times 1.25 \, \text{kg/m}^3 \times 546 \, K}{380 \, \text{torr} \times 273 \, K} \] **Hint:** Ensure you keep track of units when substituting values. ### Step 5: Calculate \( D_2 \) Now we perform the calculation: \[ D_2 = \frac{760 \times 1.25 \times 546}{380 \times 273} \] Calculating the numerator: \[ 760 \times 1.25 \times 546 = 1,033,500 \] Calculating the denominator: \[ 380 \times 273 = 103,740 \] Now, divide the two results: \[ D_2 = \frac{1,033,500}{103,740} \approx 9.95 \, \text{kg/m}^3 \] **Hint:** Double-check your arithmetic to ensure accuracy. ### Step 6: Convert \( D_2 \) to g/L To convert from kg/m³ to g/L, we use the conversion: 1 kg/m³ = 1 g/L. Thus: \[ D_2 \approx 9.95 \, \text{g/L} \] **Hint:** Remember that 1 kg/m³ is equivalent to 1 g/L. ### Final Answer The density of the gas at STP is approximately: \[ \boxed{9.95 \, \text{g/L}} \]
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