Due to the application of a force on a body of mass 100 kg that is initially at rest, the body moves with an acceleration of `20ms^(-2)` in the direction of the force. Find the magnitude of the force.

Answer

To solve the problem, we will apply Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula can be expressed as:

\[ F = m \cdot a \]

Where:
- \( F \) is the net force,
- \( m \) is the mass of the object,
- \( a \) is the acceleration of the object.

### Step-by-Step Solution:

1. **Identify the given values:**
- Mass of the body, \( m = 100 \, \text{kg} \)
- Acceleration of the body, \( a = 20 \, \text{m/s}^2 \)

2. **Substitute the values into the formula:**
\[ F = m \cdot a \]
\[ F = 100 \, \text{kg} \cdot 20 \, \text{m/s}^2 \]

3. **Calculate the force:**
\[ F = 2000 \, \text{kg} \cdot \text{m/s}^2 \]
Since \( 1 \, \text{kg} \cdot \text{m/s}^2 \) is equivalent to 1 Newton (N), we can express the force in Newtons:
\[ F = 2000 \, \text{N} \]

4. **Conclusion:**
The magnitude of the force applied to the body is \( 2000 \, \text{N} \).