The resultant of vecA and vecB makes an ...

The resultant of `vecA and vecB` makes an angle `alpha` with `vecA` and `beta and vecB`,

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true and (R) is not the correct explanation of (A)

(A) is true but (R) is false

Both (A) and (R) are fals

Verified by Experts

The correct Answer is:

MOTION IN A PLANE
AAKASH SERIES|Exercise EXERCISE-IB (Resolution of vectors )|1 Videos
MOTION IN A PLANE
AAKASH SERIES|Exercise EXERCISE-IB (Motion in a plane )|3 Videos
MOTION IN A PLANE
AAKASH SERIES|Exercise EXERCISE-IB (Vectors and Scalars)|5 Videos
MAGNETISM
AAKASH SERIES|Exercise ADDITIONAL EXERCISE|22 Videos
MOTION IN A PLANE
AAKASH SERIES|Exercise QUESTION FOR DESCRIPTIVE ANSWER|7 Videos

Two vectors vecA and vecB inclined at an angle theta have a resultant vecR which makes an angle alpha with vecA and angle beta with vecB . Let the magnitudes of the vectors vecA, vecB and vecR be represented by A, B and R respectively. Which of the following relations is not correct ?

`(R)/(sin(alpha+beta))=(A)/(sin alpha) = (B)/(sin beta)`

`R sin alpha = B sin (alpha + beta)`

`A sin alpha = B sin beta`

`R sin beta = A sin (alpha + beta)`

`((A sin theta))/((A^(2) +B^(2)cos^(2)theta)) `

`((2AB sin theta))/((A^(2) -B^(2)cos^(2)theta)) `

`((A^(2) sin^(2) theta))/((A^(2) +B^(2)cos^(2)theta)) `

`((B^(2) sin^(2) theta))/((A^(2) -B^(2)cos^(2)theta)) `

`pi//2`

`pi`

zero

any angle between zero and `pi`