The order of `Cl - O` bond energy in `ClO^(-), ClO_(2)^(-), ClO_(3)^(-), CIO_(4)^(-)` is

Options

A. `ClO^(-) gt ClO_(2)^(-) gt ClO_(3)^(-) gt ClO_(4)^(-)`
B. `ClO_(4)^(-) gt ClO_(3)^(-) gt ClO_(2)^(-) gt ClO^(-)`
C. `ClO_(4)^(-) gt ClO_(2)^(-) gt ClO_(3)^(-) gt ClO^(-)`
D. `ClO_(3)^(-) gt ClO^(-) gt ClO_(2)^(-) gt ClO_(4)^(-)`

Answer

To determine the order of Cl-O bond energy in the ions ClO^(-), ClO2^(-), ClO3^(-), and ClO4^(-), we will follow these steps:

### Step 1: Draw the Lewis Structures
We need to draw the Lewis structures for each of the ions to understand their bonding.

1. **ClO^(-)**: Chlorine is bonded to one oxygen atom with a single bond and has a negative charge.
2. **ClO2^(-)**: Chlorine is bonded to two oxygen atoms. One oxygen is double-bonded, and the other is single-bonded, with resonance structures possible.
3. **ClO3^(-)**: Chlorine is bonded to three oxygen atoms, with one double bond and two single bonds, allowing for resonance structures.
4. **ClO4^(-)**: Chlorine is bonded to four oxygen atoms, with one double bond and three single bonds, allowing for resonance structures.

### Step 2: Determine the Bond Order
The bond order can be calculated using the formula:
\[ \text{Bond Order} = \frac{\text{Number of bonds around central atom participating in resonance}}{\text{Total number of resonating structures}} \]

1. **For ClO^(-)**:
- Number of bonds = 1 (single bond)
- Resonating structures = 1
- Bond Order = \( \frac{1}{1} = 1 \)

2. **For ClO2^(-)**:
- Number of bonds = 3 (1 double bond + 1 single bond)
- Resonating structures = 2
- Bond Order = \( \frac{3}{2} = 1.5 \)

3. **For ClO3^(-)**:
- Number of bonds = 5 (1 double bond + 2 single bonds)
- Resonating structures = 3
- Bond Order = \( \frac{5}{3} \approx 1.67 \)

4. **For ClO4^(-)**:
- Number of bonds = 7 (1 double bond + 3 single bonds)
- Resonating structures = 4
- Bond Order = \( \frac{7}{4} = 1.75 \)

### Step 3: Relate Bond Order to Bond Energy
Bond energy is directly proportional to bond order. Therefore, the higher the bond order, the higher the bond energy.

### Step 4: Order the Bond Energies
Based on the bond orders calculated:
- ClO^(-): Bond Order = 1
- ClO2^(-): Bond Order = 1.5
- ClO3^(-): Bond Order ≈ 1.67
- ClO4^(-): Bond Order = 1.75

The order of bond energy from lowest to highest is:
1. ClO^(-) (lowest bond energy)
2. ClO2^(-)
3. ClO3^(-)
4. ClO4^(-) (highest bond energy)

### Final Answer
The order of Cl-O bond energy is:
**ClO^(-) < ClO2^(-) < ClO3^(-) < ClO4^(-)**