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If a circle of radius 4 touches x-axis a...

If a circle of radius 4 touches x-axis at (2,0) then its centre may be

A

(2,2)(2,-2)

B

(2,4)(2,-4)

C

(4,2)(4,-2)

D

(4,4)(4,-4)

Text Solution

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The correct Answer is:
To find the center of a circle with a radius of 4 that touches the x-axis at the point (2, 0), we can follow these steps: ### Step 1: Understand the properties of the circle A circle that touches the x-axis means that the distance from the center of the circle to the x-axis is equal to the radius of the circle. ### Step 2: Identify the coordinates of the touching point The circle touches the x-axis at the point (2, 0). This means that the x-coordinate of the center of the circle is also 2, since the center must be directly above or below the touching point. ### Step 3: Determine the y-coordinate of the center Since the radius of the circle is 4, and it touches the x-axis, the distance from the center to the x-axis must be 4 units. The center can either be above or below the x-axis: - If the center is above the x-axis, the y-coordinate will be \(0 + 4 = 4\). - If the center is below the x-axis, the y-coordinate will be \(0 - 4 = -4\). ### Step 4: Write the coordinates of the center Thus, the possible coordinates for the center of the circle are: 1. \( (2, 4) \) (above the x-axis) 2. \( (2, -4) \) (below the x-axis) ### Conclusion The center of the circle may be either \( (2, 4) \) or \( (2, -4) \).
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Knowledge Check

  • A circle centre (1,2) touches y-axis. Radius of the circle is

    A
    2
    B
    3
    C
    1
    D
    4
  • The equation of the circle which touches x-axis and whose centre is (1,2) is

    A
    (a) `x^(2) + y^(2)- 2x - 4y + 4 = 0 `
    B
    (b) `x^(2) + y^(2) - 2x - 4y + 1= 0 `
    C
    (c) ` x^(2) + y^(2) + 2x + 4y - 1 = 0 `
    D
    (d) `x^(2) + y^(2) + 2x - 4y + 1 = 0 `
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