Home
Class 11
CHEMISTRY
The wave length of two photons A and B a...

The wave length of two photons A and B are 100 Å and 100 nm. The ratio of their energies will be

A

`1:1`

B

`2:1`

C

`10:1`

D

`1:10`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the energies of two photons A and B with wavelengths of 100 Å and 100 nm, we can follow these steps: ### Step 1: Understand the relationship between energy and wavelength The energy (E) of a photon is related to its wavelength (λ) by the formula: \[ E = \frac{hc}{\lambda} \] where: - \( E \) is the energy of the photon, - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J s} \)), - \( c \) is the speed of light (\( 3.00 \times 10^8 \, \text{m/s} \)), - \( \lambda \) is the wavelength of the photon. ### Step 2: Convert wavelengths to meters We need to convert the given wavelengths from Ångströms and nanometers to meters: - Wavelength of photon A (λ₁) = 100 Å = \( 100 \times 10^{-10} \, \text{m} = 1 \times 10^{-8} \, \text{m} \) - Wavelength of photon B (λ₂) = 100 nm = \( 100 \times 10^{-9} \, \text{m} = 1 \times 10^{-7} \, \text{m} \) ### Step 3: Write the energy formulas for both photons Using the energy formula, we can express the energies of photons A and B: - Energy of photon A (E₁): \[ E_1 = \frac{hc}{\lambda_1} = \frac{hc}{1 \times 10^{-8}} \] - Energy of photon B (E₂): \[ E_2 = \frac{hc}{\lambda_2} = \frac{hc}{1 \times 10^{-7}} \] ### Step 4: Find the ratio of their energies Now, we can find the ratio of the energies: \[ \frac{E_1}{E_2} = \frac{\frac{hc}{\lambda_1}}{\frac{hc}{\lambda_2}} = \frac{\lambda_2}{\lambda_1} \] Substituting the values of λ₁ and λ₂: \[ \frac{E_1}{E_2} = \frac{1 \times 10^{-7}}{1 \times 10^{-8}} = 10 \] ### Step 5: Conclusion The ratio of the energies of the two photons A and B is: \[ \frac{E_1}{E_2} = 10 \] ### Final Answer The ratio of their energies \( E_1 : E_2 = 10 : 1 \). ---
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

Two stars A and B radiate maximum energy at wave lengths 4000Å and 5000Å respectively. The ratio of their temperature will be-

The ratio of wavelength of a photon and that of an electron of same energy E will be

Knowledge Check

  • A proton has kinetic energy E = 100 keV which is equal to that of a photon. The wavelength of photon is lamda_(2) and that of proton is lamda_(1) . The ratio of lamda_(2)//lamda_(1) is proportional to

    A
    `E^(2)`
    B
    `E^(1//2)`
    C
    `E^(-1)`
    D
    `E^(-1//2)`
  • There are two sources of light, each emitting with a power of 100W . One emits X-rays of wavelength 1nm and the other visible light at 500nm . Find the ratio of number of photons of X-rays to the photons of visible light of the given wavelength?

    A
    `1:500`
    B
    `1:400`
    C
    `1:300`
    D
    `1:200`
  • Similar Questions

    Explore conceptually related problems

    The energy of a 700- nm photon is :-

    The amplitude of two waves are in ratio 5 : 2. If all other conditions for the two waves are same, then what is the ratio of their energy densities

    There are two sources of light, each emitting with a power of 100W . One emits X-rays of wavelength 1nm and the other visible light at 500nm . Find the ratio of number of photons of X-rays to the photons of visible light of the given wavelength?

    The two paricles A and B have de Broglie wavelengths 1 nm and 5 nm respectively if mass of A is four times the mass of B, the ratio of kinetic energies of A and B would be :-

    S_1 and S_2 are two coherent sources of radiations separated by distance 100.25 lambda , where lambda is the wave length of radiation. S_1 leads S_2 in phase by pi//2 .A and B are two points on the line joining S_1 and S_2 as shown in figure.The ratio of amplitudes of component waves from source S_1 and S_2 at A and B are in ratio 1:2. The ratio of intensity at A to that of B (I_A/I_B) is

    S_1 and S_2 are two coherent sources of radiations separated by distance 100.25 lambda , where lambda is the wave length of radiation. S_1 leads S_2 in phase by pi//2 .A and B are two points on the line joining S_1 and S_2 as shown in figure.The ratio of amplitudes of component waves from source S_1 and S_2 at A and B are in ratio 1:2. The ratio of intensity at A to that of B (I_A/I_B) is