Home
Class 11
BIOLOGY
The rate of a reaction doubles or decrea...

The rate of a reaction doubles or decreases by half when temperature changes by

A

`1^(@)C`

B

`5^(@)C`

C

`10 ^(@)C`

D

`25^(@)C`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding how the rate of a reaction changes with temperature, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship Between Temperature and Reaction Rate**: - The rate of a chemical reaction typically increases with an increase in temperature. This is due to the fact that higher temperatures provide more energy to the reactant molecules, leading to more frequent and effective collisions. 2. **The Rule of Thumb**: - A common rule of thumb in chemistry is that for many reactions, the rate of reaction doubles for every 10 degrees Celsius increase in temperature. Conversely, the rate of reaction is halved for every 10 degrees Celsius decrease in temperature. 3. **Applying the Rule**: - Given that the rate of reaction doubles or decreases by half, we can conclude that this change corresponds to a temperature change of 10 degrees Celsius. - Therefore, if the rate doubles, the temperature must have increased by 10 degrees Celsius. If the rate decreases by half, the temperature must have decreased by 10 degrees Celsius. 4. **Conclusion**: - The answer to the question is that the rate of a reaction doubles or decreases by half when the temperature changes by **10 degrees Celsius**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • BIOMOLECULES

    AAKASH SERIES|Exercise EXERCISE - I (Enzymes Inhibition)|10 Videos

  • BIOMOLECULES

    AAKASH SERIES|Exercise EXERCISE - I (Classification and Nomenclature of Enzymes)|24 Videos

  • BIOMOLECULES

    AAKASH SERIES|Exercise EXERCISE - I (Properties & Nature of enzyme Action)|11 Videos

  • BIOLOGICAL CLASSIFICATION

    AAKASH SERIES|Exercise EXERCISE-III (Previous AIPMT/NEET Question)|37 Videos

  • CELL CYCLE AND CELL DIVISION

    AAKASH SERIES|Exercise Exercise-III|18 Videos

Similar Questions

Explore conceptually related problems

The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 JK^(-1) mol^(-1) )

The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 JK^(-1) mol^(-1) )

The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 JK^(-1) mol^(-1) )

(a) Explain the following terms : (i) Order of a reaction (ii) Molecularity of a reaction (b) The rate of a reaction increases four times when the temperature changes from 300 K to 320 K. Calculate the energy of activation of the reaction, assuming that it does not change with temperature. (R = 8.314 J K^(-1) mol^(-1))

The rate of a reaction doubles when its temperature changes from 300 K to 310 K . Activation energy of such a reaction will be: (R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)

The rate of a reaction A doubles on increasing the temperature from 300 to 310 K. By how much, the temperature of reaction B should be increased from 300 K so that rate doubles if activation energy of the reaction B is twice to that of reaction A

If the rate of reaction increases by 27 times , when temperature is increased by 30 K, then temperature coefficient of the reaction is

The rate of a reaction gets doubled when temperature increase by 27^(@) C "to" 37^(@) . By what factor will it change for the temperature range 17^(@) C to 27^(@) C

The rate of a reaction quadruples when the temperature changes from 293K to 313K . Calculate the energy of activation of the reaction assuming that it does not change with temperature.

The rate of reaction is doubled for every 10^(@)C rise in temperature. The increase in rate as result of an increase in temperature from 10^(@)C to 100^(@)C is how many times of the original rate?

Home
Profile