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(A) : The radiation force on an absorbin...

(A) : The radiation force on an absorbing surface is twice that on a reflecting surface. (R) : The radiation force on a reflecting surface is twice that on an absorbing surface.

A

Both 'A' and 'R' are true and 'R' is the correct explanation of 'A'.

B

Both 'A' and ’R' are true and 'R' is not the correct explanation of 'A

C

A' is true and 'R' is false

D

'A' is false and R' is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both the assertion (A) and the reason (R) regarding the radiation force on absorbing and reflecting surfaces. ### Step-by-Step Solution: 1. **Understanding Radiation Force**: - The radiation force on a surface depends on how the surface interacts with incident electromagnetic radiation. There are two types of surfaces to consider: absorbing surfaces and reflecting surfaces. 2. **Radiation Force on Absorbing Surface**: - When electromagnetic radiation strikes an absorbing surface, the energy is absorbed, and the radiation force can be calculated using the formula: \[ F_a = \frac{I}{c} \] where \( F_a \) is the radiation force on the absorbing surface, \( I \) is the intensity of the radiation, and \( c \) is the speed of light. 3. **Radiation Force on Reflecting Surface**: - For a reflecting surface, the radiation force is different because the radiation is reflected rather than absorbed. The force on a perfectly reflecting surface is given by: \[ F_r = \frac{2I}{c} \] where \( F_r \) is the radiation force on the reflecting surface. This is because the momentum change is double when the radiation is reflected. 4. **Comparing the Forces**: - From the above equations, we can see that: \[ F_r = 2 F_a \] This means the radiation force on a reflecting surface is twice that on an absorbing surface. 5. **Evaluating the Assertion and Reason**: - **Assertion (A)**: "The radiation force on an absorbing surface is twice that on a reflecting surface." This statement is **false** because we established that the force on a reflecting surface is actually twice that on an absorbing surface. - **Reason (R)**: "The radiation force on a reflecting surface is twice that on an absorbing surface." This statement is **true** based on our calculations. 6. **Conclusion**: - Therefore, the assertion (A) is false, and the reason (R) is true. The correct answer is that A is false and R is true. ### Final Answer: - Assertion (A) is false, and Reason (R) is true.
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AAKASH SERIES-ELECTROMAGNETIC WAVES-EXERCISE -IB
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