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(A): If a conducting medium is placed be...

(A): If a conducting medium is placed between two charges, then electric force between them becomes zero.
(R ): Reduction in a force due to introduced material is inversely proportional to its dielectric constant.

A

Both .A. and .R. are true and .R. is the correct explanation of .A.

B

Both .A. and .R. are tru and .R. is not the correct explanation of .A.

C

A. is true and .R. is false

D

A. is false and .R. is true

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given statements (A) and (R), we will break down the concepts involved and provide a step-by-step solution. ### Step-by-Step Solution: 1. **Understanding Statement (A)**: - The statement claims that if a conducting medium is placed between two charges, the electric force between them becomes zero. - In electrostatics, when a conductor is placed in an electric field, it polarizes and redistributes its charges. This redistribution creates an opposing electric field that cancels the original field between the two charges. 2. **Effect of a Conductor**: - When a conducting medium is placed between two point charges \( q_1 \) and \( q_2 \), the charges on the conductor will rearrange such that the electric field inside the conductor is zero. - As a result, the net electric field between the two charges becomes zero, leading to zero force between them. 3. **Understanding Statement (R)**: - The reasoning states that the reduction in force due to the introduced material is inversely proportional to its dielectric constant. - The dielectric constant \( k \) is a measure of how much a material can reduce the electric field compared to a vacuum. 4. **Force in a Dielectric Medium**: - The electrostatic force \( F \) between two charges in a vacuum is given by: \[ F = \frac{1}{4 \pi \epsilon_0} \frac{q_1 q_2}{r^2} \] - When a dielectric medium is introduced, the force becomes: \[ F' = \frac{1}{4 \pi \epsilon_0 k} \frac{q_1 q_2}{r^2} \] - As the dielectric constant \( k \) increases, the force \( F' \) decreases, indicating that the force is inversely proportional to \( k \). 5. **Conclusion**: - Since the conducting medium effectively cancels the electric field between the charges, the force becomes zero. - The reasoning that the reduction in force is inversely proportional to the dielectric constant is also correct because, for a conductor, \( k \) approaches infinity, leading to a force of zero. - Therefore, both statements (A) and (R) are true, and (R) is the correct explanation of (A). ### Final Answer: Both (A) and (R) are true, and (R) is the correct explanation of (A).
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AAKASH SERIES-ELECTRIC CHARGES AND FIELDS-Exercise-I
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  17. Assertion : In a cavity within a conductor, the electric field is zero...

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