The number of electric lines of force originating from a charge of 1C is

Options

A. `1.129 xx 10^(11)`
B. zero
C. `1.129 xx 10^(-11)`
D. `1.129 xx 10^(10)`

Answer

To find the number of electric lines of force originating from a charge of 1 Coulomb, we can use the formula:

\[ N = \frac{q}{\epsilon_0} \]

where:
- \( N \) is the number of electric field lines,
- \( q \) is the charge (in Coulombs),
- \( \epsilon_0 \) is the permittivity of free space, which is approximately \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2 \).

### Step-by-step Solution:

1. **Identify the charge**:
The charge \( q \) is given as \( 1 \, \text{C} \).

2. **Identify the permittivity of free space**:
The value of \( \epsilon_0 \) is \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2 \).

3. **Substitute the values into the formula**:
\[ N = \frac{1 \, \text{C}}{8.85 \times 10^{-12} \, \text{C}^2/\text{N m}^2} \]

4. **Calculate the number of electric field lines**:
\[ N = \frac{1}{8.85 \times 10^{-12}} \approx 1.129 \times 10^{11} \]

5. **Conclusion**:
The number of electric lines of force originating from a charge of 1 Coulomb is approximately \( 1.129 \times 10^{11} \).