Home
Class 12
PHYSICS
The linear charge density on a dielectri...

The linear charge density on a dielectric ring of radius `R` vanes with `theta` as `lambda = lambda_0 cos theta//2`, where `lambda_0` is constant. Find the potential at the center `O` of the ring [in volt].

Text Solution

Verified by Experts

The correct Answer is:
0
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROSTATICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED) MATRIX MATCHING TYPE QUESTIONS)|1 Videos

  • ELECTROMAGNETICS

    AAKASH SERIES|Exercise ADDITIONAL EXERCISE|13 Videos

  • ELEMENTS OF VECTORS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|10 Videos

Similar Questions

Explore conceptually related problems

The linear charge density on a ring of radius R is lambda=lambda_0 sin (theta) where lambda_0 is a constant and theta is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

A thin nonconducting ring of radius R has a linear charge density lambda = lambda_(0) cos varphi , where lambda_(0) is a constant , phi is the azimuthal angle. Find the magnitude of the electric field strength (a) at the centre of the ring , (b) on the axis of the ring as a function of the distance x from its centre. Investegation the obtained function at x gt gt R .

the linear charge density of a thin metallic rod varies with the distance x from the end as lambda=lambda_(0)x^(2)(0 le x lel) The total charge on the rod is

A ring of radius R carries a non - uniform charge of linear density lambda = lambda_(0)costheta sec in the figure) Magnitude of the net dipolement of the ring is :

A half ring of radius r has a linear charge density lambda .The potential at the centre of the half ring is

Linear mass density of a rod AB(of length 10 m) varies with distance x from its end A as lambda = lambda_0x^3 ( lambda_0 is positive constant) . Distance of centre of mass of the rod , from end B is

Linear mass density of a rod AB ( of length 10 m) varied with distance x from its end A as lambda = lambda_0 x^3 ( lamda_0 is poitive constant). Distance of centre of mass the rod, form end B is

The given two fixed rings of radius R lie in XY plane as shown in the figure. Linear charge density of the rings A and B varies as per the relation lambda=lambda_(0)sintheta and lambda=lambda_(0)costheta respectively where theta is measured from +x axis. Distance between the centre of the two rings is r gt gt R

The linear charge density on upper half of semi-circular section of ring is lambda and that at lower half is -lambda . The direction of electric field at centre O of ring is :

The set of values of lambda in R such that tan^2 theta + sec theta = lambda holds for some theta is

Home
Profile