Home
Class 12
PHYSICS
Consider the situation shown in figure. ...

Consider the situation shown in figure. The plates of the capacitor have plate area A and are clamped in the laboratory, the dielectric slab is released from rest with a length a inside the capacitor. Neglecting any effect of friction or gravity . Show that the slab will execute periodic motion and find its time period.

A

`8sqrt(((l-a)lmd)/(epsilon_0Aepsilon^2(K-1)))`

B

`8sqrt(((l-a)lmd)/(epsilon_0Aepsilon^2(K+1)))`

C

`8sqrt(((l+a)lmd)/(epsilon_0Aepsilon^2(K+1)))`

D

`8sqrt(((l+a)md)/(epsilon_0Aepsilon^2(K+1)))`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CAPACITORS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - IV) (LEVEL - II (ADVANCED)) (More than one correct answer Type Questions )|3 Videos

  • CAPACITORS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - IV) (LEVEL - II (ADVANCED)) (Matrix Matching Type Questions)|1 Videos

  • CAPACITORS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - IV) (LEVEL - I (MAIN)) Straight Objective Type Questions)|8 Videos

  • ATOMS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|21 Videos

  • COMMUNICATION SYSTEM

    AAKASH SERIES|Exercise LECTURE SHEET (LEVEL - I) (MAIN) (EXERCISE - IV) (Straight Objective & More than one Correct Answer Type Questions)|20 Videos

Similar Questions

Explore conceptually related problems

The plates of the parallel plate capacitor have plate area A and are clamped in the laboratory as shown in figure. The dielectric slab of mass m, length 2l and width 2l is released from rest with length l inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period. (plates of capacitor are square plates of side 2l)

Concider the situation shown in figure .The width of each plate is b.The capacitor plates are rigidly clamped in the laboratory and connected to be a battery of emf epsilon All surfaces are frictionless .Calculate the value of M for which the dielectric slab will stay in equilibrium.

Consider the situation shown in figure. Show that if the blocks are displaced slightly in opposite directions and released, they will execute simple harmonic motion. Calculate the time period.

Consider the situastion shown in figure. Show that if that blocks are displaced slightly in opposite directions and released, they will execute simple harmonic motion. Calculate the time period.

Consider the situation shown in figure. Initially the spring is unstretched when the system is released from rest. Assuming no friction in the puley, find the maximum eleongation of the spring.

A parallel plate capacitor of capacitance C (without dielectric) is filled by dielectric slabs as shown in figure. Then the new capacitance of the capacitor is

Figure shows two parallel plate capacitors with fixed plates and connected to two batteriers. The separation between the plates is the same for the two capacitors. The plates are rectangular in shape with width b and lengths l_1 and l_2 . The left half of the dielectric slab has a dielectric constant K_1 and the right half K_2 Neglecting any friction, find the ratio of the emf of the left battery to that of the right battary for which the dielectric slab may remain in equilibrium

An air-cored capacitor of plate area A and separation d has a capacity C. Two dielectric slabs are inserted between its plates in two different manners as shown. Calculate the capacitance in each case.

Find the capacitances of the capacitance of the capacitors shown In figure .The plate area is A and the separation between the plate is d . Different dielectric slabe in a particular part of the figure area of the same thickness and the entire gap between the plate is filled with the dielectric slabs.

A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that covers 1//3 of the area of its plates, as shown in the figure. The total capacitance of the capacitor is C while that of the portion with dielectric in between is C_1 . When the capacitor is charged, the plate area covered by the dielectric gets charge Q_1 and the rest of the area gets charge Q_2 . The electric field in the dielectric is E_1 and that in the other portion is E_2 . Choose the correct option/options, ignoring edge effects.

Home
Profile