Home
Class 12
PHYSICS
Both the capacitors shown in figure are ...

Both the capacitors shown in figure are made of square plates of edge a. The separatiopn between the plates of the capacitors are `d_1 and d_2` as shown in the figure. A potential difference V is applied between the points a and b. An electron is projected between the plates of the upper capacitor along the central line. With what minimum speed should the electron be projected so that it does not collide with any plate ? Consider only the electric forces.

A

`[("Vea"^2)/(md_(2)(d_1-d_2))]^(1//2)`

B

`[("Vea"^2)/(md_(1)(d_1+d_2))]^(1//2)`

C

`[("Vea"^2)/(md_(2)(d_1-d_2))]^(2)`

D

`[("Vea"^2)/(md_(1)(d_1+d_2))]^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CAPACITORS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - I) (LEVEL - I (MAIN)) (Straight Objective Type Questions)|9 Videos

  • CAPACITORS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - I) (LEVEL - II (ADVANCED)) (Straight Objective Type Questions)|4 Videos

  • CAPACITORS

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE - IV) (LEVEL - II (ADVANCED)) (Integer Type Questions )|3 Videos

  • ATOMS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|21 Videos

  • COMMUNICATION SYSTEM

    AAKASH SERIES|Exercise LECTURE SHEET (LEVEL - I) (MAIN) (EXERCISE - IV) (Straight Objective & More than one Correct Answer Type Questions)|20 Videos

Similar Questions

Explore conceptually related problems

Both the capacitors shown in figure are made of square plates of edge a . The separations between the plates of the capacitors and d_(1) and d_(2) as shown in the figure. A battery of V volt and a resistance R are connected as shown in figure. At steady state an electron is projected between the plates of the lower capacitor from its lower plate along the plate as shown. Minimum speed should the electron be projected is given by (1)/(sqrt(n))((Vea^(2))/(md^(2)))^(1//2) so that it does not collide with any plate? Consider only the electric forces then find the value of n.

Force of attraction between the plates of a parallel plate capacitor is

An insulator plate is passed between the plates of a capacitor. Then current .

As the distance between the plates of a parallel plate capacitor decreased

A parallel plate air capacitor has capcity C distance of separtion between plates is d and potential difference V is applied between the plates force of attraction between the plates of the parallel plate air capacitor is

Three different types of dielectric slabs have been arranged between the plates of a parallel plate capacitor, as shown in the figure. The equivalent capacitance of the system between the points P and Q will be

A dielectric slab is inserted between the plates of an isolated capacitor. The force between the plates will

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.

If the separation between the plates of a capacitor is 5 mm , then area of the plate of a 3 F parallel plate capacitor is

In an isolated parallel plate capacitor of capacitance C the four surfaces have charges Q_(1), Q_(2), Q_(3) and Q_(4) as shown in the figure. The potential difference between the plates is :