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A rectangular loop of sides 8cm and 2cm ...

A rectangular loop of sides 8cm and 2cm with a small cut is kept stationary in a uniform magnetic field directed normal to the loop. The current feeding the electromagnet that produces the magnetic field is gradually reduced so that the field decreases from its initial value of 0.3T at the rate of `0.02T^(-1)`. If the cut is joined and the loop has a resistance of `1.6 Omega`, how much power is dissipated by loop as heat ? What is the source of this power ?

Text Solution

AI Generated Solution

To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the Area of the Loop The area \( A \) of the rectangular loop can be calculated using the formula: \[ A = \text{length} \times \text{width} \] Given: ...
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Knowledge Check

  • A rectangular loop of sides 6 cm 2 cm with a samll cut is moving out of a region of uniform magnetic field of magnitude 0.4 T direction normal to the loop. The voltage developed acrss the cut if velocity of loop is 2cms^(-1) in a direction normal to the longer side is

    A
    `4.8xx10^(-4)V`
    B
    `1.6xx10^(-4)V`
    C
    `2.2xx10^(-2)V`
    D
    `3.2xx10^(-2)V`