Coulomb's law relates two charges and distance between them describing the electric force as beging

Two charges spheres are separated at a distance d exert a force F on each other, if charges are doubled and distance between them is doubled then the force is

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

The gravitational force between two object is F. It masses of both object are halved without changing distance between them, then the gravitation force would become

Two charges spheres are separated at a distance d exert a force F on each other . If charges are doubled and distance between them is doubled then the force is a)F b)F/2 c)F/4 d)4F

Two charges spheres are separated at a distance d exert a force F on each other . If charges are doubled and distance between them is doubled then the force is a)F b)F/2 c)F/4 d)4F

State Coulomb's law of electric force between two charged bodies.

Coulomb's law states that the electric force becomes weaker with increasing distance. Suppose that instead, the electric force between two charged particles were independent of distance. In this case, would a neutral insulator still be attracted towards the comb.

A charge of 1 mu C is divided into parts such that their charges are in the ratio of 2: 3. These two charges are kept at a distance 1 m apart in vacuum. Then, the electric force between them (in N) is

The force of repulsion between two point charges is F, when these are at a distance of 1 m . Now the point charges are replaced by spheres of radii 25 cm having the charge same as that of point charges. The distance between their centres is 1 m , then compare the force of repulsion in two cases.

Two particles are placed at some distance. If the mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will be