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Oleum is considered as a solution of SO(...

Oleum is considered as a solution of `SO_(3)` in `H_(2)SO_(4)`, which is obtained by passing `SO_(3)` in solution of `H_(2)SO_(4)` When 100 g sample of oleum is diluted with desired mass of `H_(2)O` then the total mass of `H_(2)SO_(4)` obtained after dilution is known is known as % labelling in oleum.
For example, a oleum bottle labelled as '`109% H_(2)SO_(4)`' means the 109 g total mass of pure `H_(2)SO_(4)` will be formed when 100 g of oleum is diluted by 9 g of `H_(2)O` which combines with all the free `SO_(3)` present in oleum to form `H_(2)SO_(4)` as `SO_(3)+H_(2)O to H_(2)SO_(4)`
What is the % of free `SO_(3)` in an oleum that is labelled as `'104.5% H_(2)SO_(4)'` ?

A

10

B

20

C

40

D

None of these

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • In the prepartion of H_(2)SO_(4)

    A
    `SO_(2)` is dissolved in `H_(2)SO_(4)`
    B
    `SO_(2)` is dissolved in water
    C
    `SO_(3)` is dissolved in conc. `H_(2)SO_(4)`
    D
    `SO_(3)` is dissolved in dilute `H_(2) SO _(4)`

  • In the preparation of H_(2)SO_(4)

    A
    `SO_(2)` is dissolved in `H_(2)SO_(4)`
    B
    `SO_(2)` is dissolved in water
    C
    `SO_(3)` is dissolved in conc. `H_(2)SO_(4)`
    D
    `SO_(3)` is dissolved in dilute `H_(2)SO_(4)`

  • In the preparation of H_(2)SO_(4)

    A
    `SO_(2)` is dissolved in `H_(2)SO_(4)`
    B
    `SO_(2)` is dissolved in water
    C
    `SO_(3)` is dissolved in conc. `H_(2)SO_(4)`
    D
    `SO_(3)` is dissolved in dilute `H_(2)SO_(4)`

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    Oleum is mixture of H_(2)SO_(4) and SO_(3) i.e. H_(2)S_(2)O_(7) which is obtained by passing SO_(3) is solution of H_(2)SO_(4) . In order to dissolve SO_(3) in oleum, dilution of oleum is done by water in which oleum is converted into pure H_(2)SO as shown below: H_(2)SO_(4)+SO_(3)+H_(2)Oto2H_(2)SO_(4) (pure) When 100 gm oleum is diluted with water then total mass of diluted oleum is known as percentage labelling in oleum. For example: 109% H_(2)SO_(4) labelling of oleum sample means that 109 gm pure H_(2)SO_(4) is obtained on diluting 100 gm oleum with 9 gm H_(2)O which dissolves al free SO_(3) in oleum. If 109% H_(2)SO_(4) labelled oleum, the percent of free SO_(3) and H_(2)SO_(4) are

    Oleum or fuming H_(2)SO_(4) is

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