Home
Class 11
CHEMISTRY
A solution containing 1MXSO4(aq) and 1MY...

A solution containing `1MXSO_4(aq)` and `1MYSO_4(aq)` is electrolysed. If conc. Of `X^(2+)` is `10^(-z)M` when deposition `Y^(2+)` and `X^(2+)` starts simultaneously, calculate the value of Z.
Given: `(2.303RT)/F=0.06`
`E_(x^(2+)"|"X)^(@)=-0.12V,E_(Y^(2+)"|"Y)^(@)=-0.24V`

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

If K_(c) for the reaction Cu_((aq))^(2+) + Sn_((aq))^(2+) to Sn_((aq))^(4+) + Cu_((s)) at 25^(@) C is represented as y xx 10^(6) then find the value of y . (Given : E(Cu^(2+) |Cu)^(@) = 0.34 V , E_(Sn^(4+)|Sn^(2+))^(@) = 0.15V )

If y =e ^( m Cos ^(-1)x) then show that (1- x^(2)) y _(2) - xy_(1) -m^(2) y =0.

Knowledge Check

  • Equation of plane containing the line 2x+z-4=0,2y+z=0 and passing through the point (2,1,-1) is

    A
    `x-y-z-2=0`
    B
    `2x-y=0`
    C
    `x+2y+z-3=0`
    D
    `x+y+z-2=0`
  • Calculate the emf of the cell Cu(s) | Cu^(2+) (aq) || Ag^(+)(aq) | Ag(s) Given, E_((Cu^(2+))//(Cu))=+ 0.34 V, E_((Ag^(+))//( Ag)) = 0.80 V

    A
    + 0.46V
    B
    +1.14V
    C
    + 0.57V
    D
    -0.46V
  • If angle theta between the line (x+1)/(1) = (y-1)/(2) = (z-2)/(2) and the plane 2x - y + sqrt lamda z + 4 =0 is such that sin theta = 1/3, the value of lamda is

    A
    `(-3)/(5)`
    B
    `5/3`
    C
    `(-4)/(3)`
    D
    `3/4`
  • Similar Questions

    Explore conceptually related problems

    If m is the minimum value of f(x,y)=x^(2)-4x+y^(2)+6y when x and y are subjected to the restrictions 0lexle1and0leyle1 , then the value of |m| is ____________

    The electric field components in Fig. are E_(x)=ax^(1//2), E_(y)=E_(z)=0 , in which alpha=800N//C m^(1//2) . Calculate the flux through the cube

    If the length of the tangent from (1,2) to the circle x^(2)+y^2+x+y-4=0 and 3x^(2)+3y^(2)-x-y-lambda=0 are in the ratio 4:3 then lambda=

    If the value of equilibrium constant (K_f) for the operation Zn_((aq))^(2+) + 4OH_((aq))^(-) iff Zn(OH)_(4(aq))^(2-) is 10^(10x) , then x is (Given : Zn_((aq))^(2+) + 2e^(-) to Zn_((s)) , E^(@)=-0.76 V , Zn(OH)_(4(aq))^(2-) + 2e^(-) to Zn_((s)) + 4OH_((aq))^(-) , E^(@) = - 1.36 V , 2.303 (RT)/(F) = 0.06 )

    The transformed equation of 2x^(2)-3y^(2)+z^(2)+4x+6y-4z-2=0 when the axes are transtated to the point (-1,1,2) is