In the given reaction `PhMgBr+D_(2)O to (X)` , (X) will be :

Options

A.
B.
C.
D.

Explanation

To solve the question regarding the reaction of PhMgBr with D2O, we will break down the process step by step.

### Step 1: Identify the Reactants
The reactants in the given reaction are PhMgBr (phenylmagnesium bromide) and D2O (deuterated water).

### Step 2: Understand the Nature of PhMgBr
PhMgBr is a Grignard reagent. It has a carbon atom bonded to a phenyl group (Ph) that is negatively charged, and a magnesium bromide (MgBr) part. In this compound, the carbon atom is nucleophilic due to the partial negative charge.

### Step 3: Recognize the Role of D2O
D2O is an isotope of water where the hydrogen atoms are replaced with deuterium (D). D2O can act as a proton source in reactions with nucleophiles.

### Step 4: Reaction Mechanism
When PhMgBr reacts with D2O, the nucleophilic carbon from PhMgBr will attack the deuterium in D2O. This leads to the formation of a new bond between the carbon and deuterium.

### Step 5: Formation of Products
During this reaction, the MgBr part will dissociate from the Ph group. The result will be the formation of a phenyl group bonded to deuterium (Ph-D) and the byproduct of magnesium bromide (MgBr).

### Step 6: Final Product
The final product (X) of the reaction will be Ph-D (phenyl deuteride), and the byproduct will be MgBr.

### Conclusion
Thus, the product (X) formed from the reaction of PhMgBr with D2O is **Ph-D**.