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An electron is orbiting in 4^"th" orbit ...

An electron is orbiting in `4^"th"` orbit in a hydrogen atom. The de-broglie's wavelangth accociated with this electron is nearly

A

`1.32^@`

B

`13.2^@`

C

`15.6^@`

D

`20^@`

Text Solution

Verified by Experts

The correct Answer is:
B
`=p=sqrt(2nKM)`
`=sqrt(2 xx 9.1 xx 10^(-31) xx 0.85 xx 1.6 xx 10^(-19))`
`p=5 xx 10^(-25)`
`lambda=h/p=(6.63 xx 10^(-34))/(5 xx 10^(-25))=13.2 A`
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Knowledge Check

  • The radius of the second orbit of an electron in hydrogen atom is 2.116A . The de Broglie wavelength associated with this electron in this orbit would be

    A
    `6.64A`
    B
    `1.058A`
    C
    `2.116A`
    D
    `13.28A`

  • The De Broglie wavelenght associated with electron in n Bohr orbit is

    A
    `(2pir)/(n) A^(0)`
    B
    `2pin A^(0)`
    C
    `(1)/(n)A^(0)`
    D
    `nA^(0)`

  • What is the de-Broglie wavelength associated with the hydrogen electron in its third orbit

    A
    `9.96xx10^(-10)` cm
    B
    `9.96xx10^(-8)` cm
    C
    `9.96xx10^(4)` cm
    D
    `9.96xx10^(8)` cm

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