`A + 2B + 3C In the above reaction, 4.8 g of compound `AB_(2)C_(3)` is formed as a product when 6.0 g of A, `6.0 xx 10^(23)` atoms of B, and 0.036 mol of C are react with each other. The atomic masses of A and C are 60 and 80 amu, respectively. Find out the atomic mass of B in amu. (Given:-Avogadro no= `6 xx 10^23` )

Options

A. 40 amu
B. 60 amu
C. 70 amu
D. 50 amu

Answer

D

Explanation

Moles `{:(A +, 2B +, 3C to, AB_(2)C_(3)),(6g, 6 xx 10^(23) " atoms ", 0.036 " moles ",),(6/60, (6 xx 10^(23))/(6 xx 10^(23)),,),(0.1 "mole", 1.0 "mole", 0.036 "moles",):}`
(`0.1/1, 1.0/2, 0.036/3`, the least value is 0.012 i. e. C is Limiting Reagent
0.036 moles of C provides 0.012 moles of `AB_(2)C_(3)`
0.012 moles of `AB_(2)C_(3)` weighs 4.8 g)
1 mole of `AB_(2)C_(3)` weighs `4.8/0.012 = 400` g/moles
`400 = 60 4- 2B + 3 xx 80 B = 50` amu
B = 50 amu