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A + 2B + 3C <implies AB(2)C(3) In the...

`A + 2B + 3C In the above reaction, 4.8 g of compound `AB_(2)C_(3)` is formed as a product when 6.0 g of A, `6.0 xx 10^(23)` atoms of B, and 0.036 mol of C are react with each other. The atomic masses of A and C are 60 and 80 amu, respectively. Find out the atomic mass of B in amu. (Given:-Avogadro no= `6 xx 10^23` )

A

40 amu

B

60 amu

C

70 amu

D

50 amu

Text Solution

Verified by Experts

The correct Answer is:
D
Moles `{:(A +, 2B +, 3C to, AB_(2)C_(3)),(6g, 6 xx 10^(23) " atoms ", 0.036 " moles ",),(6/60, (6 xx 10^(23))/(6 xx 10^(23)),,),(0.1 "mole", 1.0 "mole", 0.036 "moles",):}`
(`0.1/1, 1.0/2, 0.036/3`, the least value is 0.012 i. e. C is Limiting Reagent
0.036 moles of C provides 0.012 moles of `AB_(2)C_(3)`
0.012 moles of `AB_(2)C_(3)` weighs 4.8 g)
1 mole of `AB_(2)C_(3)` weighs `4.8/0.012 = 400` g/moles
`400 = 60 4- 2B + 3 xx 80 B = 50` amu
B = 50 amu
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Knowledge Check

  • A + 2B+ 3C AB_2 C_3 Reaction of 6.0 g of A, 6.0 xx 10^(23) atoms of B, and 0.036 mol of C yields 4.8 g of compound AB_(2)C_(3) . If the atomic mass of A and C are 60 and 80 amu, respectively. The atomic mass of B is: (Avogadro number = 6 xx 10^(23) )

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    70 amu
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    D
    40 amu

  • If we take 2.2 g of CO_2, 6.02 xx 10^21 atoms of nitrogen and 0.03 gram atom of oxygen, then the molar ratio of C,N and O atom will be

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    `1:2:5`
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    `5:1:3`
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  • Two elements A and B form the compounds AB and AB_3 . If 0.25 mole of AB_2 weighs 16 g and 0.25 mole of AB_3 weighs 20, then the atomic masses of A and B are respectively

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