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Gaussian surface should not pass through...

Gaussian surface should not pass through any discrete charge because:

A

Electric field remains constant

B

Electric field becomes zero

C

Electric field due to system of discrete charge is not will defined at location at any charge

D

Electric field is continuous charge distri bution

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The correct Answer is:
To answer the question of why a Gaussian surface should not pass through any discrete charge, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Understanding Gaussian Surface**: A Gaussian surface is an imaginary closed surface used in Gauss's law to calculate electric fields. It is essential to choose the surface appropriately to simplify calculations. 2. **Gauss's Law**: Gauss's law states that the electric flux through a closed surface is proportional to the charge enclosed within that surface. Mathematically, it is given by: \[ \Phi_E = \frac{Q_{\text{enc}}}{\varepsilon_0} \] where \(\Phi_E\) is the electric flux, \(Q_{\text{enc}}\) is the total charge enclosed, and \(\varepsilon_0\) is the permittivity of free space. 3. **Effect of Discrete Charges**: When a Gaussian surface passes through a discrete charge, it does not enclose the entire charge. This means that the total charge \(Q_{\text{enc}}\) within the Gaussian surface is not well-defined. 4. **Electric Field Calculation**: If the Gaussian surface intersects a charge, the electric field at the surface is not uniform. The electric field due to a point charge varies with distance, and thus, the flux calculation becomes complicated and inaccurate. 5. **Flux Calculation Issues**: Since the electric field is not constant across the Gaussian surface when it intersects a charge, the total electric flux cannot be accurately calculated. This leads to difficulties in applying Gauss's law effectively. 6. **Conclusion**: Therefore, to ensure that the electric field can be treated uniformly and that the total flux can be accurately calculated, a Gaussian surface should not pass through any discrete charge. ### Final Answer: A Gaussian surface should not pass through any discrete charge because it complicates the calculation of electric flux due to non-uniform electric fields and makes it difficult to apply Gauss's law effectively.

To answer the question of why a Gaussian surface should not pass through any discrete charge, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Understanding Gaussian Surface**: A Gaussian surface is an imaginary closed surface used in Gauss's law to calculate electric fields. It is essential to choose the surface appropriately to simplify calculations. 2. **Gauss's Law**: ...
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Regarding a Gaussian surface mark the correct option (or) options. (A) must not pass through any discrete charge (B) must pass through any material medium (C) whether conducting or non- conducting may pass through a continuous charge distribution (D) may pass through a region where no material medium

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Knowledge Check

  • Assertion: No net charge can exist in the region where electric field is uniform. Reason: For any type of Gaussian surface selected within the region of a uniform electric field, the angle between electric field intensity and area normal is 90^@ everywhere. Hence, electric flux linked with the selected Gaussian surface is equal to zero. If the net electric flux is zero for some Gaussian surface then according to Gauss's law the net charge enclosed within the surface must be zero.

    A
    If both assertion and reason are correct and reason is a correct explanation of the assertion .
    B
    If both assertion and reason are correct but reason is not the correct explanation of assertion
    C
    If assertion is correct but reason is incorrect
    D
    If assertion is incorrect but reason is correct.
  • Assertion(A):If Gaussian surface does not enclose any charge then vec(E) at any point on the Gaussian surface must be zero. Assertion(R ):No net charge is enclosed by Gaussians surface,so net flux passing through the surface is zero.

    A
    Both `A` and `R` are true and `R` is the correct explanation of `A`
    B
    Both `A` and `R` are True but `R` is not the correct explanation of `A`.
    C
    `A` is true and `R` is false
    D
    `A` is false and `R` is true.
  • In the situatiioni when the Gaussian surface is so chosen that there are some charges inside and some outside, then regarding the electric field at any point and the electric flux through the Gaussaina surface, which of the following is correct?

    A
    The field is due to the outside charges and flux depends on the inside charges
    B
    The field is due to all the charges and flux depends on the inside charges
    C
    The field is due to all the charges and flux depends on the outside charges
    D
    The field is due to the inside charges and flux depends on the outside charges
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