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In a 500 metres race, B gives A a start ...

In a 500 metres race, B gives A a start of 160 metres. The ratio of the speeds of A and B is 2 : 3. Who wins and by how much ?

A

`6 2/3` m

B

8 m

C

`8 1/3` m

D

`6 1/3` m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine who wins the race between A and B and by how much. ### Step-by-Step Solution: 1. **Understanding the Race Setup:** - The total distance of the race is 500 meters. - A starts 160 meters ahead, which means A only has to run 500 - 160 = 340 meters. - B has to run the full 500 meters. 2. **Speed Ratio:** - The ratio of the speeds of A and B is given as 2:3. - Let's denote the speed of A as 2x and the speed of B as 3x. 3. **Time Taken to Complete the Race:** - The time taken by A to complete 340 meters can be calculated using the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \] - For A: \[ \text{Time taken by A} = \frac{340}{2x} = \frac{170}{x} \] - For B: \[ \text{Time taken by B} = \frac{500}{3x} \] 4. **Comparing the Times:** - We need to compare the times taken by A and B: \[ \text{Time taken by A} = \frac{170}{x} \] \[ \text{Time taken by B} = \frac{500}{3x} \] - To compare, we can find a common denominator or simply cross-multiply: \[ 170 \cdot 3x \quad \text{and} \quad 500 \cdot x \] \[ 510x \quad \text{and} \quad 500x \] - Since \(510x > 500x\), it follows that: \[ \frac{170}{x} < \frac{500}{3x} \] - This means A takes less time than B. 5. **Conclusion:** - A wins the race because he takes less time to complete his distance. - To find out by how much A wins, we can calculate the time difference: \[ \text{Time difference} = \frac{500}{3x} - \frac{170}{x} \] - Finding a common denominator (which is \(3x\)): \[ = \frac{500 - 510}{3x} = \frac{-10}{3x} \] - This indicates that A finishes the race before B by a certain time, but we need to convert this time difference into distance. 6. **Distance B Runs in Time A Finishes:** - We can find out how far B runs in the time it takes A to finish: \[ \text{Distance B runs in time A finishes} = \text{Speed of B} \times \text{Time taken by A} \] \[ = 3x \times \frac{170}{x} = 510 \text{ meters} \] - Since B has to run 500 meters, the distance by which A wins is: \[ 510 - 500 = 10 \text{ meters} \] ### Final Answer: A wins the race by 10 meters.
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