Lithium chloride is formed by transfer of electrons, which elements is getting oxidised in the process of formation ?

Options

A. Lithium
B. Chlorine
C. Both 1 and 2
D. None of these

Explanation

To determine which element is getting oxidized in the formation of lithium chloride (LiCl), we need to analyze the electron transfer process involved in the formation of this ionic compound.

### Step-by-Step Solution:

1. **Identify the Elements Involved**:
- The elements involved in the formation of lithium chloride are lithium (Li) and chlorine (Cl).

2. **Determine the Electronic Configuration**:
- Lithium has an atomic number of 3, and its electronic configuration is \(1s^2 2s^1\). This means lithium has one electron in its outermost shell.
- Chlorine has an atomic number of 17, and its electronic configuration is \(1s^2 2s^2 2p^6 3s^2 3p^5\). This indicates that chlorine has seven electrons in its outermost shell.

3. **Analyze the Electron Transfer**:
- Lithium can easily lose its one outer electron to achieve a stable electronic configuration (duplet) and become a lithium ion (\(Li^+\)).
- Chlorine, on the other hand, needs to gain one electron to complete its outer shell (octet) and become a chloride ion (\(Cl^-\)).

4. **Identify Oxidation and Reduction**:
- The loss of an electron by lithium is termed oxidation. Therefore, lithium is oxidized as it goes from a neutral atom (Li) to a positively charged ion (\(Li^+\)).
- The gain of an electron by chlorine is termed reduction. Thus, chlorine is reduced as it goes from a neutral atom (Cl) to a negatively charged ion (\(Cl^-\)).

5. **Conclusion**:
- In the process of forming lithium chloride, lithium is the element that gets oxidized.

### Final Answer:
**Lithium (Li) is getting oxidized in the process of formation of lithium chloride.**

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