Home
Class 12
PHYSICS
A square sheet of side 'a' is lying para...

A square sheet of side 'a' is lying parallel to XY plane at z = a The electric field in the region is `vecE = cz^2 hatk` . The electric flux through the sheet is

A

`a^4 c `

B

`1/3 a^3 c `

C

`1/3 a^4 c`

D

`0`

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • QUESTION PAPER 2022 TERM 1 SET 1

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C|6 Videos

  • QUESTION PAPER 2022 TERM 1 SET 1

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C|6 Videos

  • QUESTION PAPER 2022 SET - 5

    XII BOARDS PREVIOUS YEAR|Exercise SECTION-C (CASE STUDY)|5 Videos

  • QUESTION PAPER 2022 TERM 1 SET 2

    XII BOARDS PREVIOUS YEAR|Exercise SECTION C|6 Videos

Similar Questions

Explore conceptually related problems

Given the electric field in the region vec(E ) = 2xi , find the net electric flux through the cube and enclosed by it.

An isolated conducting sheet of area A and carrying a charge Q is placed in a uniform electric field E, such that the electric field is perpendicular to the sheet and covers all the sheet. Find out the charges appearing on its two surfaces.

Knowledge Check

  • A point charge q is placed at a distance a//2 directly above the centre of a square of side a . The electric flux through the square is

    A
    `(q)/(epsilon_(0))`
    B
    `(q)/(piepsilon_(0))`
    C
    `(q)/(4epsilon_(0))`
    D
    `(q)/(6epsilon_(0))`

  • In a region of space, the electric field is given by vecE = 8hati + 4hatj + 3hatk . The electric flux through a surface of area 100 units in the xy plane is

    A
    800 units
    B
    300 units
    C
    400 units
    D
    1500 units

  • A surface S=10hatj is kept in an electric field of vecE=3hati+5hatj+6hatk . How much electric flux will come out through the surface?

    A
    30 units
    B
    40 units
    C
    50 units
    D
    60 units

    • Similar Questions

    Explore conceptually related problems

    If the flux of the electric field through a closed surface is zero,

    Given : vecE=(10hati+7hatj)Vm^(-1) . The electric flux through 1m^(2) area is XZ plane is

    A square surface of side L in the plane of the paper is placed in a uniform electric field E acting along the same. Plane at an angle theta with the horizontal side of the square as shown in. The electric flux linked to the surface is

    The magnitude of electric field vecE in the annular region of a charged cylinderical capacitor

    A large charged metal sheet is placed in a uniform electric field, perpendicular to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_1 = 5 xx 10^5 Vm^(-1) and on the right it is E_2 = 3 xx 10^5 V m^(-1) . The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet. Assume the external field to remain constant after introducing the large sheet. Use (1/(4piepsilon_0)) = 9 xx 10^(9) Nm^(2)C^(-2)

    Home
    Profile