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How many electrons are involved in the f...

How many electrons are involved in the following redox reaction? `Cr_(2)O_(7)^(2-)` + `Fe^(2+)`+ `C_(2)O_(4)^(2-)` `to` `Cr^(3+)`+`Fe^(3+)`+`CO_(2)`
(Unbalanced)
(A)3
(B)4
(C)6
(D)5

Answer

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How many moles of electrons are involved in the conversion of 1 mol Cr_(2)O_(7)^(2-) into Cr^(3+) ion? Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O

Cr_(2) O_(7)^(2-) + C_(2) O_(4)^(2-) + H^(+) = Cr^(3+) + CO_(2) + H_(2) O

Knowledge Check

  • How many electrons are involved in the following redox reaction? Cr_(2)O_(7)^(2-)+Fe^(2+)+C_(2)O_(4)^(2-)toCr^(3+)+Fe^(3+)+CO_(2)

    A
    3
    B
    4
    C
    6
    D
    7

  • In the following redox reactionn, Cr_(2)O_(7)^(2-) + Fe^(2+) to Fe^(3+) + Cr^(3+) 1 mole of Cr_(2)O_(7)^(2-) oxidises.

    A
    1 mole of `Fe^(2+)`
    B
    3 mole of `Fe^(2+)`
    C
    4 moles `Fe^(2+)`
    D
    6 moles of `Fe^(2+)`

  • The number of electrons donated from substance(s) getting oxidized to the substance(s) getting reduced in the chemical equaton for the following reaction is: Cr_2O_(7)^(2-) + Fe^(2+) + C_2O_(4)^(2-) rarr Cr^(3+) +Fe^(3+) + CO_2 (Unbalanced)

    A
    6
    B
    5
    C
    3
    D
    4

    • Similar Questions

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    Balance the following equations in proper medium Cr_(2)O_(7)^(2-) +C_(2)H_(4)O+H^(+) rarr C_(2)H_(4)O_(2) +Cr^(3+)

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