If tan a theta-tan b theta=0, then prove...

If `tan a theta-tan b theta=0`, then prove that the values of `theta` forms an A.P.

Text Solution

Verified by Experts

We have `tan a theta = tan b theta`
`rArr a theta = n pi + b theta, n in Z`
`rArr (a -b) theta = n pi`
`rArr n pi//(a -b) = theta`
Thus, the values of `theta` form an A.P. with common difference `pi//(a -b)`

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If tan a theta - tan btheta = 0 ,then the values of theta form a series in

A.P.

G.P.

H.P.

none of these

If tan p theta= tan q theta , then the values of theta form an A.P. with common difference

`pi l (p+q)`

`pi//p`

`pi//q`

`pi(p-q)`

If tan theta + sec theta = p, then what is the value of sec theta ?

`(p ^(2) +1 )/( p ^(2))`

`(p ^(2) +1 )/( sqrtp)`

`(p ^(2) +1 )/( 2p)`

`(p +1)/(2p)`