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The number of values of a for which (a^2...

The number of values of a for which `(a^2-3a+2)x^2+(a^2-5a+6)x+a^2-4=0` is an identity in x is

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The correct Answer is:
` a = 2`
We must have `a^(2) - 3a + 2 = 0`
`rArr a = 1, 2`
and `a^(2) - 5a + 6 = 0 rArr a = 2, 3`
and `a^(2) - 4 = 0 `rArr a = pm 2`
Therefore, when a = 2, the equation will be ture for all real x .
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