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Calculate the standard enthalpy of forma...

Calculate the standard enthalpy of formation of `CH_(3)OH(l)` from the following data:
`CH_(3)OH(l)+3/2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l), …(i), Delta_(r)H_(1)^(Θ)=-726 kJ mol^(-1)`
`C(g)+O_(2)(g) rarr CO_(2)(g), …(ii), Delta_(c )H_(2)^(Θ)=-393 kJ mol^(-1)`
`H_(2)(g)+1/2O_(2)(g) rarr H_(2)O(l), ...(iii), Delta_(f)H_(3)^(Θ)=-286 kJ mol^(-1)`

Text Solution

Verified by Experts

Aim`: C(s) + 2H_(2)(g)+(1)/(2)O_(2)(g) rarr CH_(3)OH(l) , Delta_(r)H^(@) = ?`
Eqn.(ii) `+2 xx` Eqn. (iii) -Eqn. (i)gives the required eqn. with
`DeltaH = -393+2(-286) - ( -726 ) kJmol^(-1)= - 239 kJ mol^(-1)`
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Calculate the standard enthalpy of formation of CH_(3)OH (I) from the following data: CH_(3)OH (I) + 3//2O_(2) (g) rarr CO_(2) (g) + 2H_(2)O(I) , Delta_(c ) H^(theta) = - 726kJ mol^(-1) C(g) + O_(2)(g) rarr CO_(2) (g), Delta_(f) H^(theta) = - 393 kJ mol^(-1) H_(2)(g) + 1//2O_(2) (g) rarr H_(2)O (I), Delta_(f) H^(ө) - 286kJ mol^(-1)

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Knowledge Check

  • Determine enthalpy of formation for H_(2)O_(2)(l) , using the listed enthalpies of reactions: N_(2)H_(4)(l) + 2H_(2)O_(2)(l) rarr N_(2)(g) + 4H_(2)O(l), Delta_(r)H_(1)^(@) =-818 KJ//"mol" N_(2)H_(4)(l)+O_(2)(g) rarr N_(2)(g) + 2H_(2)O(l), Delta_(r)H_(2)^(@)=-622 KJ//"mol" H_(2)(g)+(1)/(2)O_(2)(g) rarr H_(2)O(l), Delta_(r)H_(3)^(@)=-285 KJ//"mol"

    A
    `-383 KJ//"mol"`
    B
    `-187 KJ//"mol"`
    C
    `-498 KJ//"mol"`
    D
    None of these

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