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The value of 1og(10) K for a reaction Ah...

The value of `1og_(10)` K for a reaction `AhArrB` is:
(Given, `Delta_(r)H_(298K)^(@)=-54.07kJ" "mol^(-1),Delta_(r)S_(298K)^(@)=10JK^(-1)" "mol^(-1) and R=8.314JK^(-1)" "mol^(-1),2.303xx8.314xx298=5705`)

A

5

B

10

C

95

D

100

Text Solution

Verified by Experts

The correct Answer is:
b
`DeltaG^(@) =DeltaH^(@) - T Delta S^(@)= - 2.303 RT log _(10) K`
`:. -2.303 RT log_(10) K= DeltaH ^(@)- T DeltaS^(@)`
i.e., `-2.303 xx 8.314 xx 298 xx log_(10)K`
`=- 54.07xx 1000 - 298 xx 10`
`-5705 log_(10)K =- 54070 - 2980 = - 57050`
or `log_(10)K =10`
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Knowledge Check

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