An alkene with molecular formula `C_7H_14` gives propanone and butanal on ozonolysis. Write down its structural formula.

Answer

To determine the structural formula of the alkene with the molecular formula C₇H₁₄ that yields propanone and butanal upon ozonolysis, we can follow these steps:

### Step 1: Understand Ozonolysis
Ozonolysis is a reaction where alkenes react with ozone (O₃) to form carbonyl compounds (aldehydes or ketones). The double bond in the alkene is cleaved, and the resulting fragments are oxidized to form these carbonyl compounds.

### Step 2: Identify the Products
The products given are propanone (which is a ketone) and butanal (which is an aldehyde). The presence of these two products suggests that the original alkene must have a double bond that, when cleaved, can yield these specific carbonyl compounds.

### Step 3: Determine the Structure of the Alkene
To produce propanone (C₃H₆O) and butanal (C₄H₈O) from an alkene, we can deduce that the alkene must have a structure that allows for the formation of these two specific products.

1. **Propanone**: This is formed from a carbon fragment that has 3 carbons.
2. **Butanal**: This is formed from a carbon fragment that has 4 carbons.

### Step 4: Construct the Alkene
Given that the alkene has 7 carbons (C₇), we can assume that the double bond is positioned such that it can yield both products. A plausible structure for the alkene is 3-heptene (CH₃-CH₂-CH=CH-CH₂-CH₂-CH₃).

### Step 5: Verify the Structure
Now, we can verify that ozonolysis of 3-heptene will yield propanone and butanal:
- The double bond in 3-heptene can be cleaved to give:
- One fragment that corresponds to propanone (C₃H₆O)
- Another fragment that corresponds to butanal (C₄H₈O)

### Final Structural Formula
The structural formula of the alkene is:
```
CH3
|
CH3-CH2-CH=CH-CH2-CH2-CH3
```