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Bond energies of H - H bond is 80 kJ/mol...

Bond energies of H - H bond is 80 kJ/mol, I - I bond is 100 kJ/mol and for H - I bond is 200 kJ/mol, the enthalpy of the reaction : `H_(2)(g) + I_(2)(g) rarr 2HI(g)` is

A

`-120` kJ

B

`200` kJ

C

`+100` kJ

D

`+120` kJ

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • Given the bond energies of N=N, H – H and N - H bonds are 945, 436 and 391 "kJ mol"^(-7) respectively, the enthalpy of the reaction N_(2(g)) + 3H_(2(g)) rarr 2 NH_(3(g)) is :

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    C
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    D
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  • If the bond energies of H-H, Br- Br and H -Br are 433, 192 and 364kJ mol^(-1) respectively, DeltaH^(@) for the reaction H_(2)(g) + Br_(2)(g) rarr 2HBr(g) is

    A
    `- 261kJ`
    B
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    C
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    D
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