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Equal volumes of solution of pH=6and pH=...

Equal volumes of solution of `pH=6and pH=8` are mixed. What will be the pH of resulting mixture?

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To find the pH of the resulting mixture when equal volumes of solutions with pH 6 and pH 8 are mixed, we can follow these steps: ### Step 1: Understand the pH Scale The pH scale is a logarithmic scale that measures the concentration of hydrogen ions (H⁺) in a solution. The formula to calculate pH is: \[ \text{pH} = -\log[\text{H}^+] \] ### Step 2: Calculate the H⁺ Concentration for Each Solution 1. For the solution with pH 6: \[ [\text{H}^+] = 10^{-6} \, \text{M} \] 2. For the solution with pH 8: \[ [\text{H}^+] = 10^{-8} \, \text{M} \] ### Step 3: Mix the Solutions When equal volumes of these two solutions are mixed, the total volume doubles, and we can calculate the new concentration of H⁺ ions in the mixture. - The total concentration of H⁺ ions from both solutions: \[ \text{Total } [\text{H}^+] = [\text{H}^+]_{pH 6} + [\text{H}^+]_{pH 8} = 10^{-6} + 10^{-8} \] ### Step 4: Calculate the New H⁺ Concentration Since we are mixing equal volumes, the concentration of H⁺ ions in the resulting mixture will be: \[ [\text{H}^+]_{\text{mixture}} = \frac{10^{-6} + 10^{-8}}{2} \] Calculating this gives: \[ [\text{H}^+]_{\text{mixture}} = \frac{10^{-6} + 0.01 \times 10^{-6}}{2} = \frac{1.01 \times 10^{-6}}{2} = 0.505 \times 10^{-6} = 5.05 \times 10^{-7} \, \text{M} \] ### Step 5: Calculate the pH of the Mixture Now we can find the pH of the resulting mixture: \[ \text{pH}_{\text{mixture}} = -\log(5.05 \times 10^{-7}) \] Using a calculator: \[ \text{pH}_{\text{mixture}} \approx 6.30 \] ### Final Answer The pH of the resulting mixture is approximately **6.30**. ---
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