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Vapour pressure of mixture of liquid A a...

Vapour pressure of mixture of liquid A and liquid B at `70^(@)C` is given by `P_(T)=180X_(B)+90(in mm)`. Where `X_(B)` is the mole fraction of B, in the liquid mixture. Calculate
(a) Vapour pressure of pure A and pure B
(b) Vapour pressure of mixture of A and B by mixing 4 g and 12 g B. (If molar mass of A and B are 2 g and 3 g respectively)
(c ) From (b) ratio of moles of A and B in vapour at `70^(@)C`

Text Solution

Verified by Experts

(a) 90 mm Hg 270 mm Hg
(b) 210 mm Hg
(c ) `1:6`
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Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (a) Vapour pressures of pure benzene and toluene at 50^(@)C .

Vapour pressures of benzene and toluene in a mixute at 50^(@)C are given in mm by P=179 X_(B)+92 where X_(B) is the mole fraction of benzene. Calculate. (b) Vapour pressure of a liquid mixture obtained by mixing 224 g benzene and 184 g of toluene.

Knowledge Check

  • Vapour pressure of pure A = 100 torr, moles = 2. Vapour pressure of pure B = 80 torr, moles = 3. Total vapour pressure of mixture is

    A
    440 torr
    B
    460 torr
    C
    180 torr
    D
    88 torr

  • Vapour pressure of pure A = 100 torr, moles = 2, vapour pressure of pure B = 80 torr, moles = 3 Total vapour pressure of mixture is

    A
    440 torr
    B
    460 torr
    C
    180 torr
    D
    88 torr

  • If x_(1) and x_(2) represent the mole fraction of a component A in the vapour phase and liquid mixture respectively and p_(A)^(@) and p_(B)^(@) represent vapours pressures of pure A and pure B. then total vapour pressure of the liquid mixture is

    A
    `(p_(A)^(@)-x_(1))/(x_(2))`
    B
    `(p_(A)^(@)-x_(2))/(x_(1))`
    C
    `(p_(B)^(@)x_(1))/(x_(2))`
    D
    `(p_(B)^(@)x_(2))/(x_(1))`

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