Vapour pressure of mixture of liquid A and liquid B at `70^(@)C` is given by `P_(T)=180X_(B)+90(in mm)`. Where `X_(B)` is the mole fraction of B, in the liquid mixture. Calculate
(a) Vapour pressure of pure A and pure B
(b) Vapour pressure of mixture of A and B by mixing 4 g and 12 g B. (If molar mass of A and B are 2 g and 3 g respectively)
(c ) From (b) ratio of moles of A and B in vapour at `70^(@)C`

Explanation

(a) 90 mm Hg 270 mm Hg
(b) 210 mm Hg
(c ) `1:6`