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Find the distance of the point (-2, 3, -...

Find the distance of the point (-2, 3, -5) from the line `(x+2)/1=(y-3)/2=z/3.`

Text Solution

Verified by Experts

The correct Answer is:
`(5sqrt(5))/sqrt(14)`
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Knowledge Check

  • The distance of the point (-2,4,-5) from the line (x+3)/(3)=(y-4)/(5)=(z+8)/(6) is

    A
    `(sqrt(37))/(10)`
    B
    `sqrt((37)/(10))`
    C
    `(37)/(sqrt(10))`
    D
    `(37)/(10)`

    • Similar Questions

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    the distance of the point (2,3,4) from the line (1-x)=(y)/(2)=(1)/(3)(1+z)

    Find the distance of a point (2,4,-1) from the line (x+5)/1=(y+3)/4=(z-6)/(-9) .

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    The distance of the point P(3,8,2) from the line (x-1)/(2)=(y-3)/(4)=(z-2)/(3) measured parallel to the plane 3x+2y-2z+17=0 is

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