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STATEMENT-1 Let veca,vecb bo two vectors...

STATEMENT-1 Let `veca,vecb` bo two vectors such that `veca.vecb=0`, then `veca` and `vecb` are perpendicular. And
STATEMENT-2 Two non-zero vectors are perpendicular if and only if their dot product is zero.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False

D

Statement-1 is False, Statement-2 is True

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If veca , vecb are two vectors such that | (veca+vecb)=|veca| then prove that 2 veca + vecb is perpendicular to vecb.

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Knowledge Check

  • If veca and vecb are two vectors such that veca.vecb = 0 and veca xx vecb = vec0 , then

    A
    `veca` is parallel to `vecb`
    B
    `veca` is perpendicular to `vecb`
    C
    either `veca` or `vecb` is a null vector
    D
    none of these

  • If veca, vecb, vecc are vectors such that veca.vecb=0 and veca + vecb = vecc then:

    A
    `|veca|^(2) + |vecb|^(2) = |vecc|^(2)`
    B
    `|veca|^(2) = |vecb|^(2) + |vecc|^(2)`
    C
    `|vecb|^(2) = |veca|^(2) + |vecc|^(2)`
    D
    None of these

  • If veca and vecb are non - zero vectors such that |veca + vecb| = |veca - 2vecb| then

    A
    `2 veca. vecb= |vecb|^(2)`
    B
    ` veca. vecb= |vecb|^(2)`
    C
    least value of `veca . Vecb + 1/(|vecb|^(2) + 2) " is " sqrt2`
    D
    least value of `veca .vecb + 1/(|vecb|^(2) + 2) " is " sqrt2 -1 `

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    Let veca,vecb,vecc be three non-zero vectors such that [vecavecbvecc]=|veca||vecb||vecc| then

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