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The dipole momnet of KCI is 3.336 xx 10^...

The dipole momnet of `KCI` is `3.336 xx 10^(-29) Cm` which indicates that it is a highly polar molecules. The inter atomic distance between `K^(o+)` and `CI^(Theta)` in this molecules is `2.6 xx10^(-10)` m Calculate the dipole moment of `KCI` molecule if there were opposite charges of one fundamental unit located at each nucleus Calculate the ionic character percentage of `KCI` .

Text Solution

Verified by Experts

If there were opposite charges of one fundamental unit , i.e., `q = 1 . 602 xx10^(-19)` coulombs, then
`mu = q xxd =(1.602 xx1-^(-19)` coulombs )`xx(2.6 xx10^(-10)m)`
`= 4.1652 xx10^(-29)` coulomb metre
`mu_("observed")= 3.336xx10^(-29)` coulomb metre
`therefore %` ionic character = `(3.336xx10^(-29))/(4.1652 xx10^(-29))xx100 = 80.09%`
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