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The observed value of dipole moment of H...

The observed value of dipole moment of `H_(2)O`
molecule is found to be 1 .84 D. Calculate the
`H-O-H` bond angle in `H_(2)O` molecule ,
given that the bond moment of O-H bond is 1.5 D.

Text Solution

AI Generated Solution

To calculate the H-O-H bond angle in the H₂O molecule using the given dipole moments, we can follow these steps: ### Step 1: Understand the Dipole Moment The dipole moment (μ) of a molecule is a vector quantity that depends on the individual bond dipole moments and their angles. For H₂O, we have two O-H bonds contributing to the overall dipole moment. ### Step 2: Define the Given Values - Observed dipole moment of H₂O (μ) = 1.84 D - Bond dipole moment of O-H (μ_OH) = 1.5 D ...
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The net dipole moment of H_(2)O molecule is

The O-O-H bond angle in H_(2)O_(2) is:

Knowledge Check

  • Bond angle in H_(2)O is

    A
    `104.5^(@)`
    B
    `120^(@)`
    C
    `109.5^(@)`
    D
    `107^(@)`
  • The O-O-H bond angle in H_(2)O_(2) is

    A
    106°
    B
    109°28'
    C
    120°
    D
    97°
  • The H-O-O bond angle in H_(2)O_(2) is

    A
    `107.28^(@)`
    B
    `109.28^(@)`
    C
    `104.5^(@)`
    D
    `97^(@)`
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