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A bulb containing N(2)O(4) is colourless...

A bulb containing `N_(2)O_(4)` is colourless in ice. Its colour inboiling water is `………….` while in water at 298 K, it is ` ………… .`

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To solve the question regarding the color of dinitrogen tetroxide (N₂O₄) at different temperatures, we will analyze the behavior of N₂O₄ in various states. ### Step-by-Step Solution: 1. **Understanding N₂O₄ Behavior**: - N₂O₄ is a colorless gas at lower temperatures. When it is cooled (like in ice), it remains colorless. 2. **Color in Boiling Water**: - When N₂O₄ is heated, it partially dissociates into nitrogen dioxide (NO₂), which is a brown gas. - At boiling water temperature (100°C or 373 K), the equilibrium shifts towards NO₂, resulting in a reddish-brown color. **Color in boiling water**: Reddish brown. 3. **Color at 298 K (25°C)**: - At room temperature (298 K), N₂O₄ is still in equilibrium with NO₂, but the concentration of NO₂ is less compared to boiling water. - This results in a pale brown color due to the presence of some NO₂, but not as intense as at boiling temperature. **Color at 298 K**: Pale brown. ### Final Answer: - Color in boiling water: **Reddish brown** - Color at 298 K: **Pale brown** ---
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Knowledge Check

  • The concentration of water molecules in pure water at 298 K is

    A
    `10^(-7)M`
    B
    `55.5M`
    C
    `5.55M`
    D
    `7.26M`
  • Which of the following is least soluble in water at 298 K?

    A
    `CH_(3)NH_(2)`
    B
    `(CH_(3))_(3)N`
    C
    `(CH_(3))_(2)NH`
    D
    `C_(6)H_(5)NH_(2)`
  • N_(2)O_(4) reacts with water to produce

    A
    `N_(2)O and HNO_(3)`
    B
    `HNO_(3) and N_(2)O_(3)`
    C
    `HNO_(2) and NO`
    D
    `HNO_(2) and HNO_(3)`
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