The vapour density of fully dissociated ...

The vapour density of fully dissociated `NH_(4)Cl` would be

double than that of `NH_(4)Cl`

half than that of `NH_(4)Cl`

same as that of `NH_(4)Cl`

determined by the amount of solid `NH_(4)Cl` taken

Text Solution

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The correct Answer is:

`NH(4)Cl to NH_(3) + HCl .` Thus , 1 mole of `NH_(4)Cl` on dissociation produces 2 moles of the vapour (1 mole `NH_(3)` and 1 mole HCl) which will have double the volume at the same temperature and pressure . As density `prop 1//volume` , therefore density will be halved .

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