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Calculate the simultaneous solubilities ...

Calculate the simultaneous solubilities of `AgSCN` and `AgBr`.
`K_(sp) (AgSCN) = 1.0 xx 10^(-12), K_(sp) (AgBr) = 5.0 xx 10^(-13)`

Text Solution

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Suppose the simultaneous solubility of AgCNS and AgBr in water are a and b respectively.
`{:(AgCNS hArr Ag^(+) + CNS^(-) , AgBr hArr Ag^(+) + Br^(-)),(" a a"," b b"):}`
Thus, `[Ag^(+)] = a+b , [ CNS^(-)] = a, [Br^(-) ] = b `
`K_(sp) ` of AgCNS `= [Ag^(+)] [ CNS^(-)]= a (a+b)`
`:. a(a+b) = 5 xx 10^(-12) " " ...(i)`
`K_(sp) "of" AgBr = [Ag^(+)][Br^(-)]=b (a+b)`
`:. b(a+b) = 5 xx 10^(-13) " " ...(ii)`
Dividing eqn. (i) by (ii), we get
`(a)/(b) = (10^(-12))/(5xx10^(-13))=2 or a = 2b`
Putting this value in eqn. (i)
`2b(2b+b) = 10^(-12) or 6b^(2) = 10^(-12) or b^(2) = 1/6 xx 10^(-12)`
or, `b= 4.08xx10^(-7) "mol" L^(-1) `
`a=2b=2xx4.08xx10^(-7) "mol" L^(-1) = 8.16xx10^(-7) "mol " L^(-1)`.
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Knowledge Check

  • The solubility of AgCl in 0.2 M NaCl is [K_(sp) AgCl =1.8 xx 10^(-10)]

    A
    `1.8 xx 10^(-11)M`
    B
    `9.0 xx 10^(-10)M`
    C
    `6.5 xx 10^(12)M`
    D
    `5.6 xx 10^(-11)M`
  • The solubility of AgCl in 0.1 M NaCl is ( K_(sp) of AgCl = 1.2 xx 10^(-10) )

    A
    `0.05 M`
    B
    `1.2 xx 10^(-6)`
    C
    `2 xx 10^(-5)`
    D
    `1.2 xx 10^(-9)`
  • If the solubility of AgCl in 0.1 M NaCl is ( K_(sp) of AgCl = 1.2 xx 10^(-10) )

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