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Upon heatingKClO(3) in presence of catal...

Upon heating`KClO_(3)` in presence of catalytic amount of `MnO_(2)`, a gas `W` is formed. Excess amount of `W` reacts with white phosphorus to given `X`. The reaction of `X` with pure `HNO_(3)` gives `Y` and `Z`.
Y and Z are, respectively

A

`N_(2)O_(5)andHPO_(3)`

B

`N_(2)O_(3)andH_(3)PO_(4)`

C

`N_(2)O_(4)andH_(3)PO_(3)`

D

`N_(2)O_(4)andHPO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`2KClO_(3)overset(MnO_(2),Delta)to2KCl+underset((W))(3O_(3))`
`P_(4)+10O_(2)overset("Oxidation")tounderset((X))(P_(4)O_(10))`
`P_(4)O_(10)` acts as dehydrating agent and removes `H_(2)O` from `HNO_(3)` to give `N_(2)O_(5)` (Y) and itself gets converted into `HPO_(3)` (Z).
Thus, X is `P_(4)O_(10)` Y is `N_(2)O_(5)`, and Z in `HPO_(3)` and W is `O_(2)`.
`P_(4)O_(10)+4HNO_(3)tounderset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))`
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