Home
Class 12
CHEMISTRY
Calculate the EMF of the following conce...

Calculate the EMF of the following concentration cell at 298K
`Zn|ZnSO_(4)(0.05M)||ZnSO_(4)(0.5M)|Zn`

Text Solution

AI Generated Solution

To calculate the EMF of the concentration cell `Zn|ZnSO4(0.05M)||ZnSO4(0.5M)|Zn` at 298 K, we will follow these steps: ### Step 1: Identify the Anode and Cathode In a concentration cell, the side with the lower concentration acts as the anode, and the side with the higher concentration acts as the cathode. Here: - Anode: `Zn|ZnSO4(0.05M)` - Cathode: `Zn|ZnSO4(0.5M)` ### Step 2: Write the Half-Reactions ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    PRADEEP|Exercise Curiosity Question|5 Videos
  • ELECTROCHEMISTRY

    PRADEEP|Exercise Problem for Practice|80 Videos
  • ELECTROCHEMISTRY

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|25 Videos
  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise IMPORTANT QUESTIONS|30 Videos
  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    PRADEEP|Exercise Curiosity Questions|2 Videos

Similar Questions

Explore conceptually related problems

Calculate the potential of the following cell reaction at 298K Sn^(4+)(1.50M)+Zn(s)toSn^(2+)(0.50M)+Zn^(2+)(2.0M) The standard potential E^(@) of the cell is 0.89 V. whether the potential of the cell will increase or decrease, if the concentration of Sn^(4+) is increased in the cell? (R=8.314JK^(-1)mol^(-1),F=96500" C "mol^(-1))

Calculate the potential of the following cell reaction at 258 K Sn^(4+)(1.50 M)+Zn(s) to Sn^(2+)(0.5 M) +Zn^(2+)(2.0 M) Standard potential of the cell is 0.89 v. s

Knowledge Check

  • Calculate EMF of following cell at 298 K Zn|ZnSO_(4) (0.1 M) ||CuSO_(4) (1.0 M)|Cu (s) if E_(cell) = 2.0 V

    A
    `2.0296 V `
    B
    `2.0592 V`
    C
    `1.0508 V `
    D
    `2.0` V
  • Statement 1: The standard emf (E_(cell)^(@)) of following concentration cell is zero. Zn(s)|ZnSO_(4)(C_(1))||ZnSO_(4)(C_(2))|Zn(s) Statement 2: The electrolyte concentration cell will be is greater in cathodic half-cell.

    A
    Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1
    B
    Statement 1 is true, statement 2 is true, statement 2 is not a correct explanation for statement 1
    C
    Statement 1 is true, statement 2 is false
    D
    statement 1 is false,statement 2 is true
  • In a concentration cell, Zn|Zn^(2+) (0.1M) || Zn^(2+) (0.15M) | Zn , as the cell discharges:

    A
    reaction proceeds to the right
    B
    the two solutions approach each other in concentration.
    C
    no reaction takes place
    D
    water gets decomposed.
  • Similar Questions

    Explore conceptually related problems

    Calcualte the EMF of the following cell Zn|Zn^(2+)(0.01M)||Zn^(2+)(0.1M)|Zn at 298K

    Name the type of the following reaction : Zn + H_(2)SO_(4) to ZnSO_(4) +H_(2)

    Calculate the EMF of a Daniel cell when the concentartion of ZnSO_(4) and CuSO_(4) are 0.001M and 0.1M respectively. The standard potential of the cell is 1.1V .

    Does the following reaction occur ? Cu + ZnSO_(4) to CuSO_(4) + Zn

    CuSO_(4)+Zn(s) to ZnSO_(4)+Cu