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(a) The molar conductivities at infinite...

(a) The molar conductivities at infinite dilution of potassium chloride, hydrochloric acid and potassium acetate are 130.1, 379.4 and 95.6 S `cm^(2)mol^(-1)` respectively. Calculate the value of molar conductivity at infinite dilution for acetic acid.
(b) If the molar conductivity of given acetic acid solution is 48.5 S `cm^(2)mol^(-1)` at `25^(@)C`, calculate the degree of dissociation of acetic for acetic acid.

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To solve the given problem, we will follow these steps: ### Part (a): Calculate the molar conductivity at infinite dilution for acetic acid. 1. **Identify the known values**: - Molar conductivity at infinite dilution of KCl (Λ°(KCl)) = 130.1 S cm² mol⁻¹ - Molar conductivity at infinite dilution of HCl (Λ°(HCl)) = 379.4 S cm² mol⁻¹ - Molar conductivity at infinite dilution of KAc (Λ°(KAc)) = 95.6 S cm² mol⁻¹ 2. **Write the expression for the molar conductivity of acetic acid (CH₃COOH)**: The molar conductivity at infinite dilution of a weak acid (like acetic acid) can be calculated using the following relationship: \[ \Lambda°(CH₃COOH) = \Lambda°(HCl) + \Lambda°(KAc) - \Lambda°(KCl) \] 3. **Substitute the known values into the equation**: \[ \Lambda°(CH₃COOH) = 379.4 + 95.6 - 130.1 \] 4. **Calculate the value**: \[ \Lambda°(CH₃COOH) = 379.4 + 95.6 - 130.1 = 345.0 \, \text{S cm}^2 \text{mol}^{-1} \] ### Part (b): Calculate the degree of dissociation of acetic acid. 1. **Identify the known values**: - Molar conductivity of acetic acid solution (Λ) = 48.5 S cm² mol⁻¹ - Molar conductivity at infinite dilution of acetic acid (Λ°(CH₃COOH)) = 345.0 S cm² mol⁻¹ (calculated in part a) 2. **Use the formula for degree of dissociation (α)**: The degree of dissociation (α) can be calculated using the formula: \[ \alpha = \frac{\Lambda}{\Lambda°(CH₃COOH)} \] 3. **Substitute the known values into the equation**: \[ \alpha = \frac{48.5}{345.0} \] 4. **Calculate the value**: \[ \alpha = 0.1401 \, \text{or} \, 14.01\% \] ### Final Answers: (a) The molar conductivity at infinite dilution for acetic acid is **345.0 S cm² mol⁻¹**. (b) The degree of dissociation of acetic acid is **14.01%**.

To solve the given problem, we will follow these steps: ### Part (a): Calculate the molar conductivity at infinite dilution for acetic acid. 1. **Identify the known values**: - Molar conductivity at infinite dilution of KCl (Λ°(KCl)) = 130.1 S cm² mol⁻¹ - Molar conductivity at infinite dilution of HCl (Λ°(HCl)) = 379.4 S cm² mol⁻¹ - Molar conductivity at infinite dilution of KAc (Λ°(KAc)) = 95.6 S cm² mol⁻¹ ...
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Knowledge Check

  • The molar conductivity of acetic acid at infinite dilution is 390.7 Scm^(2) "mol"^(-1) . Conductivity of 0.1 M acetic acid solution is 5.2 S cm^2 "mol"^(-1) , find out degree of dissociation of acetic acid :-

    A
    0.133
    B
    0.0133
    C
    0.139
    D
    0.001
  • The increase in the molar conductivity of acetic acid with dilution is due to

    A
    decrease in interionic forces
    B
    increase in degree of ionisation
    C
    increase in self ionisation of water
    D
    None of the above
  • The increase in the value of molar conductivity of acetic acid with dilution is due to

    A
    decrease in interionic forces
    B
    increase in degree of ionisation
    C
    increase in self ionisation of water
    D
    none of these.
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