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On electrolysis of an aqueous solution N...

On electrolysis of an aqueous solution NaCl, why `H_(2)` and not Na is liberated at the cathode?

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To understand why hydrogen gas (H₂) is liberated at the cathode during the electrolysis of an aqueous solution of sodium chloride (NaCl) instead of sodium metal (Na), we can break down the explanation into several steps: ### Step 1: Understanding Electrolysis Electrolysis is a process that uses electrical energy to drive a non-spontaneous chemical reaction. In the case of an aqueous NaCl solution, the electrolysis involves the movement of ions towards the electrodes. ### Step 2: Ionization of NaCl in Water When NaCl is dissolved in water, it dissociates into sodium ions (Na⁺) and chloride ions (Cl⁻): \[ \text{NaCl} \rightarrow \text{Na}^+ + \text{Cl}^- \] ...
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Explain why electrolysis of aqueous solution of NaCl gives H_(2) at cathode and Cl_(2) at anode. Write the overall reaction. [Given : E_(Na^(+)//Na)^(@) = -2.71 V, E_(Cl_(2)//2Cl^(-))^(@) = 1.36 V ] 1/2 O_(2)(g) + 2H^(+) (aq) + 2e^(-) to H_(2)O (l), E^(@) = 1.23 V

During electrolysis of a concentrated aqueous solution of NaCl , what is the product at anode ?

Knowledge Check

  • In the electrolysis of an aqueous solution of NaOH , 2.8 litres of O_(2)(g) is liberated at the anode at NTP . Volume of hydrogen gas liberated at the cathode at NTP will be

    A
    `2.8` litres
    B
    `5.6` litres
    C
    `1.4` litres
    D
    `11.2` litres

  • In the electrolysis of aqueous solution of NaOH, 2.8 litre-of oxygen was librated at the anode at NTP. How much hydrogern was liberated at the cathode?

    A
    5.6 litre
    B
    66 Paise
    C
    560 ml
    D
    Rs.6.60

  • In the electrolysis of an aqueous solution of NaF , the product obtained at the cathode and anode respectively are

    A
    `Na , F_(2)`
    B
    `Na, O_(2)`
    C
    `H_(2) , O_(2)`
    D
    `H_(2) , F_(2)`

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