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What is meant by limiting molar conducti...

What is meant by limiting molar conductivity?

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**Step-by-Step Solution:** 1. **Definition of Molar Conductivity:** Molar conductivity (Λ) is defined as the conductivity (κ) of an electrolyte solution divided by its molar concentration (C). It indicates how well an electrolyte conducts electricity in a solution. \[ \Lambda = \frac{\kappa}{C} \] ...
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Read the given passage and answer the questions number that follow : Molar conductivity increases with decrease in concentration. This is because the total volume, V, of solution containing one mole of electrolyte also increases. It has been found that decrease in K on dilution of a solution is more than compensated by increase in its volume. Physically, it means that at a given concentration, Am can be defined as the conductance of the electrolytic solution kept between the electrodes of a conductivity cell at unit distance but having area of cross-section large enough to accommodate sufficient volume of solution that contains one mole of the electrolyte. When concentration approaches zero, the molar conductivity is known as limiting molar conductivity and is represented by the symbol Lambda_(m) The variation in Am with concentration is different for strong and weak electrolytes. Why is meant by limiting molar conductivity ?

When concentration of the solution approaches zero, the molar conductivity is known as limiting molar conductivity.

Knowledge Check

  • A saturated solution in AgA (K_(sp)=3xx10^(-14)) and AgB (K_(sp)=1xx10^(-14)) has conductivity of 375xx10^(-10) S cm^(-1) and limiting molar conductivity of Ag^(+) and A^(-) are 60S cm^(2) "mol"^(-1) and 80 S cm^(2) "mol"^(-1) respectively , then what will be the limiting molar conductivity of B^(-) (in S cm^(2) "mol"^(-1) )?

    A
    150
    B
    180
    C
    190
    D
    270

  • Limiting molar conductivity of NaBr is

    A
    `Lambda_m^@NaBr = Lambda_m^@NaCl + Lambda_m^@KBr`
    B
    `Lambda_m^@NaBr = Lambda_m^@ NaCl + Lambda_m^@KBr - Lambda_m^@KCl`
    C
    `Lambda_m^@NaBr=Lambda_m^@NaOH + Lambda_m^@NaBr - Lambda_m^@NaCl`
    D
    `Lambda_m^@NaBr=Lambda_m^@NaCl-Lambda_m^@NaBr`

  • Which one of the following ions has highest limiting molar conductivity?

    A
    `Na^(+)`
    B
    `Mg^(2+)`
    C
    `K^(+)`
    D
    `Ca^(2+)`

    • Similar Questions

    Explore conceptually related problems

    (a) State the law which helps to determine the limiting molar conductivity of weak electrolytes. (b) Calculate limiting molar conductivity of CaSO^4 (limiting molar conductivity of calcium and sulphate ions are 119.0 and 106.0 S cm^2 mol^(-1) respectively).

    According to Kohlrausch law, the limiting molar conductivity of an electrolyte, A_(m)B_(n) , can be expressed as

    Assertion: If lamda_(Na)^(o)+lamda_(Cl^(-))^(o) are molar limiting conductivity of the sodium and chloride ions respectively, then the limiting molar conductivity for sodium chloride is given by the equation: ^^_(NaCl)^(o)=lamda_(Na^(+))^(o)+lamda_(Cl^(-))^(o) . Reason: This is according to Kohlrausch law of independent migration of ions.

    _________ Law of independent migration of ions states that limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte.

    ___________ Law of independent migration of ions states that limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of the anion and cation of the electrolyte.

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