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Assertion (A) : In a Daniell cell, if th...

Assertion `(A) :` In a Daniell cell, if the concentration of `Cu^(2+)` and `Zn^(2+)` ions are doubled, the `EMF` of the cell will be doubled.
Reason `(R) :` If the concentration of ions in contact with metals is doubled, the electrode potential is doubled.

A

If both assertion and reason are true, and reason is the true explanation of the assertion

B

if both assertion and reason are true, but reason is not the true explanation of the assertion.

C

if assertion is true, but reason is false.

D

If both assertion and reason are false.

Text Solution

Verified by Experts

The correct Answer is:
D

Correct A. `Zn+Cu^(2+)toZn^(2+)+Cu,E_(cell)=E_(cell)^(@)-(RT)/(nF)"ln"([Zn^(2+)])/([Cu^(2+)])`
Thus, if `[Zn^(2+)]` and `[Cu^(2+)]` are doubled, there is no effect of emf.
Correct R. `Cu^(2+)+2e^(-)toCu,E=E^(@)-(RT)/(nF)"ln"(1)/([Cu^(2+)])`
Thus, if `[C^(2+)]` is doubled, E is not doubled.
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Statement-I: In the Daniel cell, if concentration of Cu^(2+) and Zn^(2+) ions are doubled the emf of the cell will not change. Because Statement-II: If the concentration of ions in contact with the metals is doubled, the electrode potential is doubled.

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Knowledge Check

  • Statement 1: In the daniel cell, if the concentration of Cu^(2+) and Zn^(2+) ions are doubled, the cell potential will be doubled. Statement 2: if the concentration of ions reversible to the electrode is doubled, the electrode potential is also doubled.

    A
    Statement 1 is true, statement 2 is true, statement 2 is a correct explanation for statement 1
    B
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    C
    Statement 1 is true, statement 2 is false
    D
    statement 1 is false,statement 2 is true
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    A
    is doubled
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    C
    remains same
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    A
    doubles
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    reduces to half
    C
    remains same
    D
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