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The atomic number of cerium (Ce) is 58...

The atomic number of cerium `(Ce)` is 58. The correct electronic confguration of `Ce^(3+)` ions is :

A

`[Xe]4f^(1)`

B

`[Kr]4f^(1)`

C

`[Xe]4f^(13)`

D

`[Kr]4d^(1)`

Text Solution

Verified by Experts

`Z = 54` is `[Xe]=Z= 56` is `Ba = [ Xe] 6s^(2)`
`Z =57` ( La) is `[Xe]5d^(1)` ( electron 5d in place of expected 4f)
But in `Z= 58` ( Ce ) , electron enters 4f and `5d^(1)` also shifts to 4f. Hence, electronic configuration of `Ce( 58) ` is `[Xe] 4f^(2) 5d^(0) 6s^(2)`.
`:. Ce^(3+) = [Xe]4f^(1)`
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Knowledge Check

  • the atomic number of cerium ( Ce ) is 58 . The correct electronic configuration of Ce^(3+) ion is

    A
    `[Xe] 4f^(1)`
    B
    `[Kr]4f^(1)`
    C
    `[Xe] 4f^(13)`
    D
    `[Kr] 4d^(1)`

  • The atomic number of cerium (Ce) is 58. The correct electronic configuration of Ce^(3+) ion is

    A
    `[Xe]4f^(1)`
    B
    `[Kr]4f^(-1)`
    C
    `[Xe]4f^(-13)`
    D
    `[Kr]4d^(1)`

  • The atomic number of Gadolinium (Gd) is 64. The CORRECT electronic configuration of Gd^(3+) ion is____________.

    A
    [Xe] `4f^7`
    B
    [Kr] `4f^7`
    C
    [Xe] `4f^(13)`
    D
    [Kr]`4f^1`

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