Given are three resistance of 3 ohms each. How can they give a total resistance of 9,1 and 2.0 ohm ? Draw suitable diagram for each case.

Explanation

Case I : When 3 resistor are connected in series . Then total R `=9 Omega`
`R=R_(1)+R_(2)+R_(3)=3+3+3=9 Omega`
Case II: When 3 resistors are connected in parallel combination. Then total R =`1 Omega`
`R=R_(1)+R_2+R_(3)=1//3+1//3+1//3=1 Omega`
Case III: When out of 3 resistor , 2 are connected in series and `3^(rd)` is connected in parallel to them `1/R=1/6 +1/3=3/6=1/2`, Then total `R =2 Omega`